Mathematical Process and Some measurement ın varargout

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Gözde Üstün 2020-5-17

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https://ww2.mathworks.cn/matlabcentral/answers/526165-mathematical-process-and-some-measurement-in-varargout

回答： Walter Roberson 2020-5-17

I have n matrices of size d*d(first 2 index of the array) for 2 different measurement(third index of the array) with d outcomes(fourth index of the array) with varargout:

function [varargout] = trying(d)
    varargout = repmat({zeros(d,d,2,d)}, 1, max(nargout,1));
    U=FourierMatrix(d);
%         for k=1:d
%             %varargout(k,k,1,k)=1;
%             varargout(:,:,2,k)=U*varargout(:,:,1,k)*U';
%         end        
end

However I cannot use these process on varargout I mean for each element(comes from user (vararggout) I have 2 possibilities ) like:

for k=1:d
            varargout(k,k,1,k)=1;
            varargout(:,:,2,k)=U*varargout(:,:,1,k)*U';
end   

And moreover the second measurement of the next element is the transpose of the previous one (In this step we can use the next element is the tranpose of the first element) like that:

B(:,:,2,k)=transpose(A(:,:,2,k));

But I could not know how can I apply this process on varargout??

(If I want to write this code for 2 element, it is easy and it will be like that:)

function [item1,item2]=trying(d)
U=FourierMatrix(d);
item1=zeros(d,d,2,d);
item2=item1;
for k=1:d
    item1(k,k,1,k)=1;
    item1(:,:,2,k)=U*item1(:,:,1,k)*U';
    item2(k,k,1,k)=1;
    item2(:,:,2,k)=transpose(item1(:,:,2,k));
end

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Gözde Üstün 2020-5-17

I am trying something like that :

function varargout = trying2(d)
varargout = cell(1,max(1,nargout));
varargout(:) = {zeros(d,d,2,d)};
for i=1:length(varargout)
    for k=1:d
        varargout(k,k,1,k)=1;
        varargout(:,:,2,k)=U*varargout(:,:,1,k)*U';
    end      
end    
end