ppmak
Put together spline in ppform
Syntax
ppmak(breaks,coefs)
ppmak
ppmak(breaks,coefs,d)
ppmak(breaks,coefs,sizec)
Description
The command ppmak(...)
puts together a spline in ppform from minimal information, with the rest inferred from that
information. fnbrk
provides any or all of the
parts of the completed description. In this way, the actual data structure used for
the storage of the ppform is easily modified without any effect on the various
fn...
commands that use this construct. However, the casual
user is not likely to use ppmak
explicitly, relying instead on
the various spline construction commands in the toolbox to construct particular
splines.
ppmak(breaks,coefs)
returns the ppform of
the spline specified by the break information in breaks
and the
coefficient information in coefs
. How that information is
interpreted depends on whether the function is univariate or multivariate, as
indicated by breaks
being a sequence or a cell array.
If breaks
is a sequence, it must be nondecreasing, with its
first entry different from its last. Then the function is assumed to be univariate,
and the various parts of its ppform are determined as follows:
The number
l
of polynomial pieces is computed aslength(breaks)
-1
, and the basic interval is, correspondingly, the interval[breaks(1)
..breaks(l+1)]
.The dimension
d
of the function's target is taken to be the number of rows incoefs
. In other words, each column ofcoefs
is taken to be one coefficient. More explicitly,coefs(:,i*k+j)
is assumed to contain thej
th coefficient of the(i+1)
st polynomial piece (with the first coefficient the highest and thek
th coefficient the lowest, or constant, coefficient). Thus, withkl
the number of columns ofcoefs
, the orderk
of the piecewise-polynomial is computed asfix(kl/l)
.
After that, the entries of coefs
are reordered, by the
command
coefs = reshape(permute(reshape(coefs,[d,k,l]),[1 3 2]),[d*l,k])
in order to conform with the internal interpretation of the coefficient array in
the ppform for a univariate spline. This only applies when you use the syntax
ppmak(breaks,coefs)
where breaks
is a
sequence (row vector), not when it is a cell-array. The permutation is not made when
you use the three-argument forms of ppmak
. For the three-argument
forms only a reshape is done, not a permute.
If breaks
is a cell array, of length m
, then
the function is assumed to be m
-variate (tensor product), and the
various parts of its ppform are determined from the input as follows:
The
m
-vector l haslength(breaks{i})-1
as itsi
th entry and, correspondingly, them
-cell array of its basic intervals has the interval[breaks{i}(1) .. breaks{i}(end)]
as itsi
th entry.The dimension
d
of the function's target and them
-vectork
of (coordinate-wise polynomial) orders of its pieces are obtained directly from the size ofcoefs
, as follows.If
coefs
is anm
-dimensional array, then the function is taken to be scalar-valued, i.e.,d
is 1, and them
-vectork
is computed assize(coefs)./l
. After that,coefs
is reshaped by the commandcoefs = reshape(coefs,[1,size(coefs)])
.If
coefs
is an (r+m
)-dimensional array, withsizec = size(c)
say, thend
is set tosizec(1:r)
, and thevector
k
is computed assizec(r+(1:m))./l
. After that,coefs
is reshaped by the commandcoefs = reshape(coefs,[prod(d),sizec(r+(1:m))])
.
Then, coefs
is interpreted as an equivalent array of size
[d,l(1),k(1),l(2),k(2),...,l(m),k(m)]
, with its
(:,i(1),r(1),i(2),r(2),...,i(m),r(m))
th entry the coefficient
of
in the local polynomial representation of the function on the (hyper)rectangle with sides
This is, in fact, the internal interpretation of the coefficient array in the ppform of a multivariate spline.
ppmak
prompts you for
breaks
and coefs
.
ppmak(breaks,coefs,d)
with
d
a positive integer, also puts together the ppform of a
spline from the information supplied, but expects the function to be univariate. In
that case, coefs
is taken to be of size
[d*l,k]
, with l
obtained as
length(breaks)-1
, and this determines the order,
k
, of the spline. With this,
coefs(i*d+j,:)
is taken to be the j
th
components of the coefficient vector for the (i+1
)st polynomial
piece.
ppmak(breaks,coefs,sizec)
with
sizec
a row vector of positive integers, also puts together
the ppform of a spline from the information supplied, but interprets
coefs
to be of size sizec
(and returns an
error when prod(size(coefs))
differs from
prod(sizec)
). This option is important only in the rare case
that the input argument coefs
is an array with one or more
trailing singleton dimensions. For, MATLAB® suppresses trailing singleton dimensions, hence, without this explicit
specification of the intended size of coefs
,
ppmak
would interpret coefs
incorrectly.
Examples
The two splines
p1 = ppmak([1 3 4],[1 2 5 6;3 4 7 8]); p2 = ppmak([1 3 4],[1 2;3 4;5 6;7 8],2);
have exactly the same ppform (2-vector-valued, of order 2). But the second command provides the coefficients in the arrangement used internally.
ppmak([0:2],[1:6])
constructs a piecewise-polynomial function
with basic interval [0
..2
] and consisting of
two pieces of order 3, with the sole interior break 1. The resulting function is
scalar, i.e., the dimension d
of its target is 1. The function
happens to be continuous at that break since the first piece is
x|→x2 +
2x + 3, while the second piece is
x|→4(x – 1)2 + 5(x–1) + 6.
When the function is univariate and the dimension d
is not
explicitly specified, then it is taken to be the row number of
coefs
. The column number should be an integer multiple of the
number l
of pieces specified by breaks
. For
example, the statement ppmak([0:2],[1:3;4:6])
leads to an error,
since the break sequence [0:2]
indicates two polynomial pieces,
hence an even number of columns are expected in the coefficient matrix. The modified
statement ppmak([0:1],[1:3;4:6])
specifies the parabolic curve
x|→(1,4)x2 +
(2,5)x + (3,6). In particular, the dimension
d
of its target is 2. The differently modified statement
ppmak([0:2],[1:4;5:8])
also specifies a planar curve (i.e.,
d
is 2
), but this one is piecewise linear;
its first polynomial piece
is x|→(1,5)x + (2,6).
Explicit specification of the dimension d
leads, in the
univariate case, to a different interpretation of the entries of
coefs
. Now the column number indicates the polynomial order
of the pieces, and the row number should equal d
times the number
of pieces. Thus, the statement ppmak([0:2],[1:4;5:8],2)
is in
error, while the statement ppmak([0:2],[1:4;5:8],1)
specifies a
scalar piecewise cubic whose first piece is
x|→x3 +
2x2 + 3x +
4.
If you wanted to make up the constant polynomial, with basic interval [0..1] say, whose value is the matrix eye(2), then you would have to use the full optional third argument, i.e., use the command
pp = ppmak(0:1,eye(2),[2,2,1,1]);
Finally, if you want to construct a 2-vector-valued bivariate polynomial on the rectangle [–1 .. 1] x [0 .. 1], linear in the first variable and constant in the second, say
coefs = zeros(2,2,1); coefs(:,:,1) = [1 0; 0 1];
then the straightforward
pp = ppmak({[-1 1],[0 1]},coefs);
will fail, producing a scalar-valued function of order 2 in each variable, as will
pp = ppmak({[-1 1],[0 1]},coefs,size(coefs));
while the following command will succeed:
pp = ppmak({[-1 1],[0 1]},coefs,[2 2 1]);
See the example “Intro to ppform” for other examples.