How to determine if there is a value in a string and output it as a boolean?

1 次查看（过去 30 天）
Amar
Amar 2014-2-23
评论： Amar 2014-3-2
i.e,
A = [0 1 2 3 0 0 0]
I want to write:
-----------------
if % A(a)= 1%
content
end
---------
where 1<a<end.
so if at any index in A, there exists a A='1', the if statement is true and it is executed
Thanks

请先登录，再回答此问题。

回答（2 个）

Mischa Kim
Mischa Kim 2014-2-23
编辑：Mischa Kim 2014-2-23
Amar, you could use
a = 3;
if find(A==a)
...
end
Note, that in your case A is not a string but numeric array. To compare (find) characters or sub-strings in a string you'd use strcmp.
  3 个评论
显示 1更早的评论
Mischa Kim
Mischa Kim 2014-2-23
编辑：Mischa Kim 2014-2-23
Something like:
A = {'0' '1' '2' '3' '0' '0'}; % cell array of char
a = '1';
if sum(strcmp(a,A))>0
fprintf('Character ''%s'' found in A\n',a);
else
fprintf('Character ''%s'' not found in A\n',a);
end
Jan
Jan 2014-2-23
编辑：Jan 2014-2-23
find(A==a) is tricky, because it can reply arrays without an element or withmultiple elements also. Then this is performed internally:
if all(find(A==a)) && ~isempty(find(A==a))
This implicit behaviour might be confusing, so I'd suggest to write explicitly:
if any(A==a)
While sum(strcmp(a,A))>0 is clear, the summation is less efficient than any().

请先登录，再进行评论。

David Young
David Young 2014-2-23
I think you just want
if A(a) == 1
% actions
end

类别

在 Help Center 和 File Exchange 中查找有关 Simulink 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by