How to solve this error : "index out of bounds because numel(U)=1"

Question

Younes Alaoui 2021-11-22

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1592894-how-to-solve-this-error-index-out-of-bounds-because-numel-u-1

评论： Jon 2021-11-22

Hi Everybody,

I know this question has been answered a housand times, but no solution I could find seemed to work, so this is my last resort.

Complete Error : Attempted to access U(1001); index out of bounds because numel(U)=1. Error in Identifiant>identifier (line 92) K=Y(i)/U(i);

function identifier (Y,U,Pr)
data=guidata(gcbf);
a=Y(1);
b=Y(5);
i=1;
j=1;
while (b-a<Pr && i<length(Y))
    i=i+1;
    a=Y(i);
    b=Y(i);
end
K=Y(i)/U(i);

Here is the function where the error seems to be.

And the definition of Y and U is as follows :

u=1;
U=u(:);
y=K*(1-exp(-t/tau))*U;
Y=y(:);

I understood that U has no 1001st element, because it doesn't have the same size as Y. I tried to put both as vectors, but of course it does nothing. I also tried to use the function reshape, but it doesn't seem to work either or I might be using it wrong.

Anyways if anybody has any idea on how to solve this issue i'd be glad to listen to it. Thank you!

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Answer 1

Jon 2021-11-22

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1592894-how-to-solve-this-error-index-out-of-bounds-because-numel-u-1#answer_837604

With your definition of U, U has only one element. Note you first assign a scalar (one element) variable u=1, then you assign U to equal every element U = u(:) of u, but it only has one element, so now U also has only one element. So it doesn't make sense to ask for elements with indices greater than 1.