Unable to perform assignment because brace indexing is not supported for variables of this type.

Question

Maia2022 2022-5-27

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1728090-unable-to-perform-assignment-because-brace-indexing-is-not-supported-for-variables-of-this-type

评论： Maia2022 2022-5-27

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hello,

I have these codes and I got an error for example with:

data{iBlob, 1}(4) = dec2bin(iBlob);

dec2bin(4) gives a char '100'.

As far as I know, cell arrays accept different kinds ot types so I don't understand the error here.

Also, how to convert the char '100' into a binary code 100 ?

Thank you for your help.

Best regards

Label = bwlabel(BW);
nbLabels = max(max(Label));
data = cell(nbLabels, 1);
for iBlob = 1:nbLabels
    idx = find(Label == iBlob);        
    
    % create data
    features = regionprops ( (Label==iBlob), 'Centroid' );
    data{iBlob, 1}(1) = features.Centroid(2);
    data{iBlob, 1}(2) = features.Centroid(1);
    data{iBlob, 1}(3) = iBlob;
    data{iBlob, 1}(4) = dec2bin(iBlob); % Error here: Unable to perform assignment because brace indexing is not supported for variables of this type.
end

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Maia2022 2022-5-27

Thank you.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2022-5-27

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1728090-unable-to-perform-assignment-because-brace-indexing-is-not-supported-for-variables-of-this-type#answer_972470

在 MATLAB Online 中打开

    data{iBlob, 1} = features.Centroid(2);
    data{iBlob, 2} = features.Centroid(1);
    data{iBlob, 3} = iBlob;
    data{iBlob, 4} = dec2bin(iBlob) - '0';