How to do a double fourier transform or double summation equation in Matlab?

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Hi Community,
Iam very confused to this equation, because it should be written in a double fourier transform which re very difficult for me.... SO here is the equation i should solve in my Thesis :
T is hour of the years (it can be replaced with a datenum, right?) and M is month number. I just want to know how this difficult equation should be written as a code in Matlab... Im very confused.... I think it would be written in a combination of symsum, syms, and etc, but i still doubt how to write it correctly in Matlab.... WOuld anyone lend me a hand for this equation, please... Thank you so much, everyone... /.\ /.\ /.\
  2 个评论
Hiro Yoshino
Hiro Yoshino 2022-5-30
This is not a Fourier transform but a Fourier series expansion.
Although I am unfamiliar with this type, all you need is determine A_n^m term upto 6. You may want to make a reference to this for example. Find orthogonal functions and multiply them to the given equatio and you can obtain A_n^m terms.
Tyann Hardyn
Tyann Hardyn 2022-5-31
@Hiro Im sorry, Sir. But the m actually not an exponent number just like An^m... In other ways, the equation is like this :
Iam just wonder, Is the equation use for loop or not, Sir? Thank you very much

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Walter Roberson
Walter Roberson 2022-5-30
T cannot be replaced by a datetime. datetime objects cannot be multiplied by anything.
At one level, T could potentially be replaced by a duration() object, as durations can be multiplied... but you cannot take cos() of a duration.
syms T M
syms A [6 6]
syms alpha [1 6]
syms beta [1 6]
n = (1:6).';
m = 1:6;
Sq_est = sum(sum(A .* cos(m .* T + alpha) .* cos(n .* M + beta)))
Sq_est = 
  8 个评论
Tyann Hardyn
Tyann Hardyn 2022-5-31
编辑:Tyann Hardyn 2022-5-31
Alright, Sir.. So the input of T variable is hour of the year, sir? and the M is month number (ex. January = 1, February = 2, etc), and the A is the data in T and M?

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