How to output a new matrix that swaps the position of the beginning and end of a separate matrix

Question

Liam 2022-7-5

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https://ww2.mathworks.cn/matlabcentral/answers/1753785-how-to-output-a-new-matrix-that-swaps-the-position-of-the-beginning-and-end-of-a-separate-matrix

评论： Liam 2022-7-11

The project I'm currently working on involves the use of global data with latitudes and longitudes.

I'm extracting data for an area between 13degree W and 30degree E for the longitudinal values. However the data outputed has a linear matrix so 13degree W is actually stored as 347E

My current code is below which outputs the correct data between 347 - 360 followed by zeros for 0-30degrees since the matrix doesn't return to the beginning point.

My question is whether I can simply have matrix return to column 1 when the end of the matrix is met or whether I will need to output a new matrix that swaps their position first.

Thanks for any help you can provide!

latitude=zeros(1,18);

longitude=zeros(1,43);

for i=1:18

latitude(i)=48+(i-1)*1;

end

for j=1:43

longitude(j)=347+(j-1)*1;

end

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Answer 1

Jan 2022-7-5

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1753785-how-to-output-a-new-matrix-that-swaps-the-position-of-the-beginning-and-end-of-a-separate-matrix#answer_1000610

latitude  = zeros(1,18);
longitude = zeros(1,43);
for i=1:18
    latitude(i) = 48+(i-1)*1;
end
for j=1:43
    longitude(j) = mod(347+(j-1)*1, 360);
end
% Or without loops:
latitude  = 48 + ((1:18) - 1)*1;
longitude = mod(347+((1:43) - 1)*1, 360);