How to fill an array with Nans from 11,000x43 to 32,000x43 to generate a 3D array to be able to concatenate?

Question

Andres Ulloa 2022-8-4

0
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https://ww2.mathworks.cn/matlabcentral/answers/1774105-how-to-fill-an-array-with-nans-from-11-000x43-to-32-000x43-to-generate-a-3d-array-to-be-able-to-conc

回答： Walter Roberson 2022-8-4

I'm trying to generate a 3D array with 100 different files, however when it tries to concatenate it can't because there are 30 11,000 x 43 files and 70 32,000 x 43 files. I'd like to be able to make them the same size so I can concatenate them.

In addition, I attach a file of each one as an example of the dimensions.

This is my example:

close all; clear all
P = 'D:\2021\datos_cozumel\DatosADCP2\';
S = dir(fullfile(P,'S1*.mat'));
S = natsortfiles(S); 
for k = 1:numel(S)
    F = fullfile(P,S(k).name);
    L = load(F);
    v1(k).data = L.Data.Burst_VelBeam1; 
end
vb1 = permute(cat(3,v1.data),[1,3,2]);
save('velbeam1_3.mat','vb1')

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Answer 1

Walter Roberson 2022-8-4

在 MATLAB Online 中打开

heights = structfun(@(V)size(V.data,1), v1);
maxheight = max(heights);
paddings = maxheights - heights;
for K = 1 : numel(S)
    v1(k).data = [v1(k).data; nan(paddings(K),43)];
end
vb1 = permute(cat(3,v1.data),[1,3,2]);