loop to extract rows and giving the vectors progresseiv numbers

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amoda
amoda 2022-8-6
回答： Voss 2022-8-6
Hello,
I have a matrix of size A= [70x1459], I need to extract every row i of it and putting it in a vector M_(i), so I can plot any of them with another vector B=[1x1459].
I wanted to use a loop to achieve that easily and quickly, like following to get M1,M2 etc...:
for i=1:70
M_(i)=DehnMatrix(i,:)
end
but it doesnt work, can anyone tell me what I'm messing.
thanks in advance.

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Voss
Voss 2022-8-6
Ran in:
There's no need to make each of several rows of a matrix into its own variable (M1, M2, etc.)
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval
Instead just use indexing to get the rows you need when you need them
https://www.mathworks.com/company/newsletters/articles/matrix-indexing-in-matlab.html
For example, to plot the first 25 rows of DehnMatrix:
DehnMatrix = rand(40,1459);
plot(DehnMatrix(1:25,:).')

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