A compact way to find single digit numbers (i.e. numbers between 0 and 9) and replace them with two digit numbers

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Sim
Sim 2022-8-9
评论： Sim 2022-8-11
A compact way to find single digit numbers (i.e. numbers between 0 and 9) and replace them with two digit numbers ?
For example, from:
a = [ 8
12
15
76
3
99
0];
I would like to add a zero in front of the single digit numbers:
b = [08
12
15
76
03
99
00];
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dpb
dpb 2022-8-10
No problem from me...I was just thinking you were suggesting to put the 8-bits of zeros out based on the number of bits, not on the magnitude of the contained value it could hold.
But, agreed, it's taken off on a complete tangent...

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John D'Errico
John D'Errico 2022-8-9
编辑：John D'Errico 2022-8-9
Ran in:
In MATLAB, you CANNOT store a number in a numeric format as one that has a leading zero.
If you want to convert the numbers to character form, then it is trivial. One line is sufficient.
a = [ 8
12
15
76
3
99
0];
d = dec2base(a,10)
d = 7×2 char array
'08' '12' '15' '76' '03' '99' '00'
The result is no longer usable as a number though. It is effectively only a picture of a number at that point, or perhaps I should say a caricature, if you can stand the pun.

更多回答（1 个）

dpb
dpb 2022-8-9
For what purpose and in what context? You will only be able to show the leading zeros if you convert the numeric values to some form of text in which case it's trivial
>> compose('%02d',a)
ans =
7×1 cell array
{'08'}
{'12'}
{'15'}
{'76'}
{'03'}
{'99'}
{'00'}
>>
Well, there is one other way --
>> categorical(ans)
ans =
7×1 categorical array
08
12
15
76
03
99
00
>>
but if you want a straight, ordinary double array to appear that way at the command line, just not possible.

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