Product of matrices over finite fields

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Hi all, can someone please help with the following?
Suppose we have two matrices A and B over the finite field F_2, such that:
A*B=the zero matrix
Suppose that both A and B are 2 by 2 matrices: A=(a&b\\c&d) and B=(e&f\\g&h).
How can I find all the possible combinations of a, b, c, d, e, f, g, and h over the finite field 2 that satisfy the above equation?

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John D'Errico
John D'Errico 2024-11-25,13:55
编辑:John D'Errico 2024-11-25,13:55
Even in the simple case of F_2 matrices, I'm not sure it is easy to do better than brute force. But no, you don't need to write out each matrix product. This seems to work.
m = 3;
% all possible pairs of 2x2 matrices, as base m integers, doubles
[Adoub,Bdoub] = meshgrid(0:m^4-1);
% convert those "matrices" into pages of 2x2 matrices,
% with each matrix as a plane in a 3-d matrix
Am = reshape(dec2base(Adoub,m)' - '0',[2 2 m^8]);
Bm = reshape(dec2base(Bdoub,m)' - '0',[2 2 m^8]);
% just take the product of all combinations of matrices, in F_m
AB = mod(pagemtimes(Am,Bm),m);
% and test for all zeros
zeroind = all(reshape(AB,[4,m^8]) == 0,1);
table(dec2base(Adoub(zeroind),m),dec2base(Bdoub(zeroind),m))
ans = 417x2 table
Var1 Var2 ____ ____ 0000 0000 0000 0001 0000 0002 0000 0010 0000 0011 0000 0012 0000 0020 0000 0021 0000 0022 0000 0100 0000 0101 0000 0102 0000 0110 0000 0111 0000 0112 0000 0120
There are 58 sets of matrices identified for base 2, and 417 for base 3. If m is too large of course, expect things to get nasty in terms of computations, because you will have m^8 such combinations of matrices to deal with.

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Torsten
Torsten 2024-11-24,18:30
移动:Torsten 2024-11-24,18:30
Just test the 16 x16 = 256 possible products for A and B.
  13 个评论
Walter Roberson
Walter Roberson 2024-11-25,22:20
Integer:
isinteger(x) || all(x == floor(x),'all')
but even for integer data types, if abs(x) > sqrt(intmax(class(x))) then there is the potential for overflow if two such values get multiplied together. (Of course overflow in integer class only saturates, leaving the same datatype behind... but the point is the results would be inaccurate.)

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