How do I get the relative error between 2 signals in Simulink?

I have two first order transfer functions in Simulink. One is the exact system and the other is a close approximation. How would I get the relative error between the two? I tried using an addition block to subtract the exact function from the approximation and then taking the output from the addition block and using a divide block to divide the absolute error by the output of the original transfer function to get the relative error. The addition block looks to be giving the correct absolute error, but then the divide block sends out a massive maximum relative error value, on the order of 10^23.

 采纳的回答

Assume x and y are the two signals, you are doing
abs((x-y)/x) or abs((x-y)/y), when x or y is close to zero, it will cause divided-by-zero error, or cause the result to be very large which does not represent the true relative error.

1 个评论

That's what I figured, but is there a good way to handle that or a different way to find the error?

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Simulink 的更多信息

产品

版本

R2024a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by