How to spread out an arry of matrix randomly

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Hamid Reza Barzegar
评论： Hamid Reza Barzegar 2016-5-19
I have random matrix like this
[2 2 2 2 1 1 1 1 1 -1 -1 -1 -1 -1]
and depend to the result of calculation number of 2 1 -1 will be different but i want to spread these numbers randomly like this e.g. [2 1 2 -1 1 1 2 -1 2 -1 -1 2 ]
how should i do this?

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回答（2 个）

Walter Roberson
Walter Roberson 2016-5-18
YourVector(randperm(length(YourVector)))
  2 个评论
Hamid Reza Barzegar
Hamid Reza Barzegar 2016-5-18
first=100;
Second=50;
Third=50;
Alloc_Sc=[2*ones(1,first),ones(1,Second),-1*ones(1,Third)];
Alloc_Sc2=Alloc_Sc(length(randperm(Alloc_Sc)));
it shows the error:
Error using randperm Size inputs must be scalar.
Stephen23
Stephen23 2016-5-19
@Hamid Reza Barzegar: Walter Roberson's answer clearly uses randperm(length(...)). You have written length(randperm(...).

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Roger Stafford
Roger Stafford 2016-5-18
编辑：Roger Stafford 2016-5-18
Let n be the desired length of the result and let a = [2 1 -1] :
p = randi(3,n,1); % <-- Corrected
v = a(p(randperm(n))); % v is your result % <-- Corrected
  5 个评论
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Roger Stafford
Roger Stafford 2016-5-18
As I state above, your expression is in error in using "length(randperm(Alloc_Sc))" instead of "randperm(length(Alloc_Sc))".
Hamid Reza Barzegar
Hamid Reza Barzegar 2016-5-19
Thanks for your reply i changed as you mentioned but the data is returned is number between 1 to 200 not my data now there is no error but not my data
first=100;
Second=50;
Third=50;
Alloc_Sc=[2*ones(1,first),ones(1,Second),-1*ones(1,Third)];
Alloc_Sc2=randperm(length(Alloc_Sc));

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