Sum of each row ?

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Trevor Badji
Trevor Badji 2017-12-10
评论： Image Analyst 2017-12-26
I have [1 1 0; 0 1 0; 0 0 0;] and I want to write that if average of each row > 0.5 it equals 1 , else 0
for the example above, first row 1+1+0 / 3 > 0.5 then it is 1 ..
for i=1:length(nx);
s(i)= sum(nx(i,:))/3;
for n=1:length(nx);
if s(i(n+1))> 0.5;
s(i(n+1)) == 1;
else
s(i(n+1))== 0 ;
end
end
end
  2 个评论
Star Strider
Star Strider 2017-12-10
What functions are you permitted to use in this obvious homework assignment?
Rena Berman
Rena Berman 2017-12-26
(Answers Dev) Restored edit

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回答（3 个）

Jos (10584)
Jos (10584) 2017-12-10
Use the matlab way! Use the functions mean, or sum and size. Read the documentation on these functions and pay attention to the dimension argument.
Then take a closer look at logical operators, like >
A = [.9 .7 .4 .6 .2]
B = A > 0.5
Image Analyst
Image Analyst 2017-12-10
编辑：Image Analyst 2017-12-10
Does it have to be a for loop? Why not just do:
rowMeans = mean(nx, 2);
s = zeros(size(nx));
s(rowMeans > 0.5, :) = 1;
You've said both "sum" and "average" - which is it?????. The above is for average. If you want sums, do
rowSums = sum(nx, 2);
s = zeros(size(nx));
s(rowSums > 0.5, :) = 1;
  3 个评论
显示 1更早的评论
Stephen23
Stephen23 2017-12-11
"There are no specific number of rows therefore i am trying to use for loop to see average of each row"
This makes no sense: vectorized code has no restrictions on how many rows it can handle. Why do you think that a loop is required?
Image Analyst
Image Analyst 2017-12-26
Original question:
I have [1 1 0; 0 1 0; 0 0 0;] and I want to write that if average of each row > 0.5 it equals 1 , else 0
for the example above, first row 1+1+0 / 3 > 0.5 then it is 1 ..
for i=1:length(nx);
s(i)= sum(nx(i,:))/3;
for n=1:length(nx);
if s(i(n+1))> 0.5;
s(i(n+1)) == 1;
else
s(i(n+1))== 0 ;
end
end
end

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Walter Roberson
Walter Roberson 2017-12-10
mean(nx, 2) > 0.5 %the 2 means "by rows" here.

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