How to find Hamming Distance ?

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Ammy
Ammy 2018-1-25
评论： Ammy 2018-1-26
I have a set of different codewords , how I separate those code words having the same hamming distance? Also D=pdist(A,'hamming') does not work in my case , If A is 1 1 1 2; 1 2 1 2 I want to calculate no. of position where they differ.
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Walter Roberson
Walter Roberson 2018-1-25
Does it happen to be the case that all of your values are either 1 or 2 ? (Or, more generally, that you have exactly two different values and the two values are numerically 1 apart ?)

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the cyclist
the cyclist 2018-1-25
编辑：the cyclist 2018-1-25
The Hamming distance is the fraction of positions that differ. If you want the number of positions that differ, you can simply multiply by the number of pairs you have:
numberPositionsDifferent = size(A,2)*pdist(A,'hamming');
If that's not what you meant, you might want to give more information (including the answer to Walter's questions in his comment.)

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