Apply function to two cell arrays element-wise

18 次查看(过去 30 天)
I have two cell arrays, xdata and CDF. I want to apply kstest element-wise to each pair of xdata and CDF cells (e.g., xdata{1} and CDF{1}, xdata{2} and CDF{2}, etc.).
Each cell of xdata is nx1 (data sample values), and each cell of CDF ix nx2 (theoretical [x,CDF] values).
I can do this with a for loop:
for i=1:length(xdata)
[h{i},p{i},ks2stat{i}]=kstest(xdata{i},CDF{i});
end
But I'm wondering if there's a clever way to do it more cleanly with anonymous functions and cellfun? Something along the lines of:
[h,p,ks2stat]=deal(cellfun(@(xc) kstest(xc(:,1),xc(:,2:3)),{[xdata CDF]},'Uniform',0));
Any ideas would be appreciated. Thanks!

采纳的回答

Guillaume
Guillaume 2018-2-2
You're overcomplicating:
[h, p, k2stat] = cellfun(@kstest, xdata, CDF, 'UniformOutput', false);
  3 个评论
Guillaume
Guillaume 2018-2-5
编辑:Guillaume 2018-2-5
"I have two cell arrays, xdata and CDF"
input #2 expected to be a cell array, was double instead
One of these statement contradicts the other.
Putting brackets around the inputs is very unlikely to be the correct fix. It would only work if both xdata and CDF were matrices, not cell array and would then be simply equivalent to:
[h, p, k2stat] = ktest(xdata, CDF);
h = {h}; p = {p}; k2stat = {k2stat}; %useless stuffing of the results in cell arrays
And if xdata and CDF were really structures then your code would certainly error. Be careful with the terms you use. cell arrays, matrices, structures, tables (another term often misused) are very different types.
dandan
dandan 2018-2-5
Oops, sorry, you're right. I was simplifying the problem to explain it here and forgot I was referencing structures in the real version. You're correct, the way you originally wrote it does work if xdata and CDF are cell arrays. Thank you and sorry for the confusion!

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by