i have a 48*48*3 matrix , i want to convert it to 48*48 matrix where each element of the matrix will show a list of 3 characters in a cell. how to do it?

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shashwat soni
shashwat soni 2018-9-14
评论： Andrei Bobrov 2018-9-14
for eg-
i need this matrix to look like {1,9} {2,7} {3,8}.......
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Image Analyst
Image Analyst 2018-9-14
编辑：Image Analyst 2018-9-14
For all the numbers, you can try this:
[rows, columns, numSlices] = size(m);
index = 1;
ca = cell(1, rows*columns); % Preallocate
for row = 1 : rows
for col = 1 : columns
ca{index} = m(row, col, :);
index = index + 1;
end
end

更多回答（2 个）

Matt J
Matt J 2018-9-14
编辑：Matt J 2018-9-14
Acell=cellfun( @(c) c(:).', num2cell(A,3), 'uni',0 );
Image Analyst
Image Analyst 2018-9-14
Did you try something like this:
[rows, columns, numSlices] = size(m);
index = 1;
ca = cell(1, rows*columns); % Preallocate
for row = 1 : rows
for col = 1 : columns
ca{index} = [m(row, col, 1), m(row, col, end)];
index = index + 1;
end
end

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