vpasolve in for loop

6 次查看(过去 30 天)
maedeh Gh
maedeh Gh 2019-2-19
I Run this code and it works correctly, but I wanna stop the for loop when it gets Empty sym: 0-by-1
for p=0:10
ub= vpasolve(function==0,x,[1000*p,1000*(p+1)])
end

回答(1 个)

Etsuo Maeda
Etsuo Maeda 2019-3-5
"vpasolve" returns numerical values. Its output "ub" cannot be a sym variable. If you use "solve", you can use "isempty" and "break" for your pourpose.
syms x
for k = 1:2
out = solve(x^k + 1 == 0, x)
if isempty(out) == 1
disp('break')
break;
end
disp('in loop')
end
HTH
  2 个评论
Walter Roberson
Walter Roberson 2019-3-5
This is not quite correct. vpasolve() returns symbolic values that represent numeric values. They are sym, and when no solution is found then the empty sym can be returned.
Also there is no need to compare isempty() to 1: you can just test if isempty(out)
Etsuo Maeda
Etsuo Maeda 2019-3-5
UUUps, thank you very much for your kind correction :-)

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