Missing factor using rule of three?

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Pawl
Pawl 2019-3-13
评论： Pawl 2019-3-13
Hello,
I try to calculate a distance in meter, given the rad values. I use the follwing formula, which is really easy.
0.004 x (m)
--------- = ----------
2*pi y (rad)
If I want to know which x(m) corresponds to 4*pi the formula becomes
(0.004*4*pi)/(2*pi)=2*0.004=0.008
This is a result I would expect, but putting the same formula into matlab or any calculator results in
(0.004*4*pi)/2*pi
ans=
0.078956
Next to a missing magnitude it is not 100% correct as well. I think one reason is limited digits of pi, but why is a magnitude missing?
I am sorry for such a trivia question, but maybe someone could give me a hint. I propably think in a wrong direction.

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采纳的回答

the cyclist
the cyclist 2019-3-13
编辑：the cyclist 2019-3-13
Try
(0.004*4*pi)/(2*pi)
The reason your syntax does not work is that it will divide by 2, and then multiply by pi.
See order of operations for details on how expressions are evaluated.

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