Sine function produces unexpected results

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Joachim Wagner
Joachim Wagner 2019-5-5
编辑： Joachim Wagner 2019-5-5
Good morning community,
I've got some troubles using the MATLAB sine function ( sin() ) and I hope somebody can help me to solve this wrong line of thought :)
However, let me describe the issue I'm troubling with. I'm trying to give the sine function a time vector and a frequency to calculate the amplitude as follow:
omega = pi; % define frequency
t = 0:.1:1; % define time vec
A = sin(1i*omega.*t)
The result I get from this operation is the following:
The strange thing and what I really don't understand is, why I do get the correct result, if I'm not using a variable for t but typing the vector definition directly in the function call command as you can see bellow:
Even if I leave off the complex number in the first case, I'm not getting the result I expect, however this shouldn't change anything.
So, I hope there is somebody, who has an idea why it behaves like this. I would be very thankful.
Best regards.

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采纳的回答

Stephan
Stephan 2019-5-5
Hi,
note:
>> t = 0:0.1:1
t =
Columns 1 through 8
0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000
Columns 9 through 11
0.8000 0.9000 1.0000
>> pi .* t
ans =
Columns 1 through 8
0 0.3142 0.6283 0.9425 1.2566 1.5708 1.8850 2.1991
Columns 9 through 11
2.5133 2.8274 3.1416
But now:
>> pi .* 0:0.1:1
ans =
Columns 1 through 8
0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000
Columns 9 through 11
0.8000 0.9000 1.0000
Using brackets makes things going to be correct:
>> pi .* (0:0.1:1)
ans =
Columns 1 through 8
0 0.3142 0.6283 0.9425 1.2566 1.5708 1.8850 2.1991
Columns 9 through 11
2.5133 2.8274 3.1416

更多回答（2 个）

Joachim Wagner
Joachim Wagner 2019-5-5
All right, that's true. Thank you very much, that fits it for the moment but can maybe still someone explain, why I get those complex numbers in the first case? I don't really get it.
  2 个评论
Star Strider
Star Strider 2019-5-5
‘The strange thing and what I really don't understand is, why I do get the correct result, if I'm not using a variable for t but typing the vector definition directly in the function call command ...’
Not really strange. It relates to the way MATLAB defined the two vectors in:
omega = pi; % define frequency
t = 0:.1:1; % define time vec
A = sin(1i*omega.*t)
and:
A = sin(1i*omega*0:.1:1)
In the first one, the imaginary operator 1i multiplies the entire vector ‘t’. In the second one, 1i multiplies only the first element of the vector, here 0 (so the first element remains 0 and is not complex) and none of the others.
The second is equivalent to the first if you put parentheses around the vector:
A = sin(1i*omega*(0:.1:1))
John D'Errico
John D'Errico 2019-5-5
It is an order of operators thing. The colon operator is quite low on the totem pole, so other operations are done first.
That means while you might expect that this operation
1 + 0:5
will add 1 to each element of the vector 0:5, in fact, it adds 1 to 0, then uses that as the first operand of colon. So we see this:
1 + 0:5
ans =
1 2 3 4 5
The same applies to what you did.

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Joachim Wagner
Joachim Wagner 2019-5-5
编辑：Joachim Wagner 2019-5-5
Right perfect, it now becomes clear. Thanks a lot to all of you!

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