How to get an y-value (y1(x)) for the sub condition of 0.8y1=0.25x

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Alexander Busch
Alexander Busch 2019-7-29
评论： Alexander Busch 2019-8-5
Hi there,
i need some help. I have two collum vectors y=force and x=settlement. Now i had to write a scribt which gives me the first y-value (y1(x)) where the subcondition: 0.8*y1=0.25x is true. I am not so familar whith loops and so I would need some help.
Thank you!
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Alexander Busch
Alexander Busch 2019-7-30
sry...
now it is this problem:
>> x=zeros(length(weg_fit_mm),1);
for
i=1+1:kraft_fit_kN(end);
x(i)=weg_fit_mm(find(0.8*kraft_fit_kN(i)))/weg_fit_mm(find(kraft_fit_kN(i)));
end
I=min(abs(x-0.25));
end
for
↑
Error: Invalid expression. Check for missing or extra characters.

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Vimal Rathod
Vimal Rathod 2019-8-2
In the code from the above comments, there is a problem with defining the for loop condition as the error was shown.
The 'i' variable should be defined in the same line as the for. And the value should not have a semicolon(;) at the end.
Here is a sample in the code which you could try.
for i=1:kraft_fit_kN(end)
You could refer to the following documentation for further details;
https://www.mathworks.com/help/matlab/ref/for.html

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