deleting a row based on index.

13 次查看（过去 30 天）
CalebJones
CalebJones 2019-9-3
评论： CalebJones 2019-9-3
HbO_index = find(xyz1 > 7.5);%link the index with the HbO table and eliminate the bad channels
HbO_good_channel = HbO;
% for i = 1 : size(HbO,2)
for l = 1 : length(HbO_index)
k = HbO_index(l);
HbO_good_channel(:,k) = [];
end
% end
HbO_index is matrix containing values which are basically index of HbO_good_channels which i want to remove.
Only the first column from HbO_good_channels it removing properly rest its removing one index prior to what is actually mentioned, it something to do with my logic. help me out please.
thank you

请先登录，再回答此问题。

采纳的回答

David
David 2019-9-3
The problem is that in your for-loop you delete the l-th column. Thereby all the indecies of the following columns change (are reduced by one). This happens in each iteration of the for-loop. If you want to remove columns "a, b, c, d" with your code you will actually remove columns "a, b+1, c+2, d+3".
You can solve your problem by starting the for loop on the end of "HBO_index" or without a for-loop:
HbO_good_channel = HbO
HbO_good_channel(:,find(xyz1 > 7.5)) = [];
  3 个评论
显示 1更早的评论
David
David 2019-9-3
You could also remove the "find" and use logical indexing for better performance:
HbO_good_channel = HbO
HbO_good_channel(:,xyz1 > 7.5) = [];

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by