Regexp with a list of keywords

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Stephan Kolb
Stephan Kolb 2019-9-10
编辑： Stephen23 2019-9-10
Hi everbody,
I'm aware regexp is a powerful tool, but I'm a newbie to this and I think my problem is an advanced one:
There is a list of keywords
keywords = {'alpha','basis','colic','druid','even'};
and I want regexp to find in a string all values after these keywords (followed by =).
For example:
str = 'basis=10,alpha=today,druid=none,even=odd,even=even';
gives
'today','10',[],'none',{'odd','even'}
Can you help me?

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采纳的回答

Stephen23
Stephen23 2019-9-10
编辑：Stephen23 2019-9-10
Using a simple lookaround assertion:
https://www.mathworks.com/help/matlab/matlab_prog/regular-expressions.html#brchk1t
>> keywords = {'alpha','basis','colic','druid','even'};
>> str = 'basis=10,alpha=today,druid=none,even=odd,even=even';
>> fun = @(k)regexp(str,sprintf('(?<=%s=)\\w+',k),'match');
>> out = cellfun(fun,keywords,'uni',0);
>> out{:}
ans =
'today'
ans =
'10'
ans =
{}
ans =
'none'
ans =
'odd' 'even'
Note that each cell of out is itself a cell array, with varying sizes. If you want to unnest the scalar cells, as you indicate in your question, then try this:
>> idx = cellfun(@isscalar,out);
>> out(idx) = [out{idx}]
out =
'today' '10' {} 'none' {1x2 cell}
>> out{:}
ans =
today
ans =
10
ans =
{}
ans =
none
ans =
'odd' 'even'
https://www.mathworks.com/help/matlab/matlab_prog/comma-separated-lists.html
https://www.mathworks.com/matlabcentral/answers/320713-how-to-operate-on-comma-separated-lists
  2 个评论
Stephen23
Stephen23 2019-9-10
Stephan Kolb's "Answer" moved here:
Hi Stephen,
thank you very much for your quick and smart answer!!!
Do you think, we can map your solution to string arrays, e.g.
str = ["basis=10","alpha=today","druid=none","even=odd","even=even"];
Thank you in advance,
Stephan
Stephen23
Stephen23 2019-9-10
编辑：Stephen23 2019-9-10
"Do you think, we can map your solution to string arrays"
Sure: use a loop or arrayfun or concatenate the data into one character vector / a scalar string or fiddle around with the cell array outputs of regexp. Whichever works for you.
But if your data really are separated (and not in one character vector as your showed in your question), then I would probably just split them at each = character, compare the 1st parts using strcmp or the like, and then use accumarray or similar to group together.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2019-9-10
keywords = {'alpha','basis','colic','druid','even'};
kv = regexp(str, '(?<name>\w+)=(?<value>\w+)', 'names');
values = cell(1, length(keywords));
[found, idx] = ismember(keywords, {kv.name});
values(found) = {kv(idx(found)).value};
  1 个评论
Stephan Kolb
Stephan Kolb 2019-9-10
Consequently, when using a string array for str, it's better to use a string array for list the list of keywords, too.
So we have:
keywords = ["alpha","basis","colic","druid","even"];
str = ["basis=10","alpha=today","druid=none","even=odd","even=even"];
Can we adapt your solution?

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