How to integrate a function u^3/(exp(u)-1) in the range of [0 0.033]??.

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Raj Kishor
Raj Kishor 2019-9-16
回答： Bjorn Gustavsson 2019-9-16
The code is as follows:
syms x
fun=x^3/(exp(x)-1)
defIntVal=int(fun,[0 0.033])
I have used integral command also in place of int
the defIntVal is giving a very complex sym type variable. How to get value from this variable???

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回答（1 个）

Bjorn Gustavsson
Bjorn Gustavsson 2019-9-16
if numerical integration is good enough:
Val = integral(@(x) x.^3./(exp(x)-1),0,0.033)
% for which I get: 1.1831e-05
HTH

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