is there any way to put two plots in one legend entry?

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Fuad Nammas
Fuad Nammas 2019-9-17
评论： Fuad Nammas 2019-9-21
is it possible to combine multiple plots in one legend entry as shown in the picture? . I tried various operations with [] and () but it didn't work.
Is there a way to put two plots in one legend entry?

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采纳的回答

Walter Roberson
Walter Roberson 2019-9-18
That happens automatically unless you do one of the following:
  • call legend with a single legend entry, such as inside a loop or trying to place the legend call for each plot() right after the associated plot(); or call legend passing in only one graphics object handle
Some of the approaches that work are:
A)
for K = 1 : 6
this_x = something(K,:);
this_y = someother(K,:);
thislegend = sprintf('R%d', K); %construct a legend string
legends{K} = thislegend; %record it
plot(this_x, this_y);
hold on
end
legend(legends);
B)
for K = 1 : 6
this_x = something(K,:);
this_y = someother(K,:);
thislegend = sprintf('R%d', K); %construct a legend string
legends{K} = thislegend; %record it
linehandles(K) = plot(this_x, this_y);
hold on
end
legend(linehandles, legends);
C)
for K = 1 : 6
this_x = something(K,:);
this_y = someother(K,:);
thislegend = sprintf('R%d', K); %construct a legend string
linehandles(K) = plot(this_x, this_y, 'DisplayName', thislegend);
hold on
end
legend(linehandles, 'show');
D)
for K = 1 : 6
this_x = something(K,:);
this_y = someother(K,:);
plot(this_x, this_y);
hold on
end
legend({'R1', 'R2', 'R3', 'R4', 'R5', 'R6'});

更多回答（1 个）

Fuad Nammas
Fuad Nammas 2019-9-18
编辑：Fuad Nammas 2019-9-18
thanks Walter Roberson but what i am asking is:
Can I put the same colored curve (please check my pic) with the the same legend.i.e., two black curves with legend R3 and the two blue curves with legend R2, etc....
I appreciate your efforts dear.
also, below you will see my matlab code
aB=9.8*10.^(-9);
q=1.6*10.^(-19);
me=0.067*9.1*10.^(-31);
h=1.0545*10.^(-34);
kb=1.38*10.^(-23);
om1=3*10.^(12);
om2=0;
B=2;
c=q./(2*pi);
R1=aB;
R2=1.2*aB;
R3=1.4*aB;
w01=h./(((me*R1.^2*(sqrt(2*pi)))));
w02=h./(((me*R2.^2*(sqrt(2*pi)))));
w03=h./(((me*R3.^2*(sqrt(2*pi)))));
T=1:1:80;
wc=q*B/me;
y=sinh(0.5.*h.*wc./(kb.*T));
w1=sqrt(w01.^2+0.25*wc.^2);
w2=sqrt(w02.^2+0.25*wc.^2);
w3=sqrt(w03.^2+0.25*wc.^2);
om01=sqrt(w1.^2-om1.^2);
om02=sqrt(w2.^2-om1.^2);
om03=sqrt(w3.^2-om1.^2);
Icm1=c.*w1.*y./sinh(h.*w1./(kb.*T))-0.5.*c.*wc;
Irel1=c.*om01.*y./sinh(h.*om01./(kb.*T))-0.5.*c.*wc;
I1=Icm1+Irel1;
Icm2=c.*w2.*y./sinh(h.*w2./(kb.*T))-0.5.*c.*wc;
Irel2=c.*om02.*y./sinh(h.*om02./(kb.*T))-0.5.*c.*wc;
I2=Icm2+Irel2;
Icm3=c.*w3.*y./sinh(h.*w3./(kb.*T))-0.5.*c.*wc;
Irel3=c.*om03.*y./sinh(h.*om03./(kb.*T))-0.5.*c.*wc;
I3=Icm3+Irel3;
om011=sqrt(w1.^2-om2.^2);
om022=sqrt(w2.^2-om2.^2);
om033=sqrt(w3.^2-om2.^2);
Icm11=c.*w1.*y./sinh(h.*w1./(kb.*T))-0.5.*c.*wc;
Irel11=c.*om011.*y./sinh(h.*om011./(kb.*T))-0.5.*c.*wc;
I11=Icm11+Irel11;
Icm22=c.*w2.*y./sinh(h.*w2./(kb.*T))-0.5.*c.*wc;
Irel22=c.*om022.*y./sinh(h.*om022./(kb.*T))-0.5.*c.*wc;
I22=Icm22+Irel22;
Icm33=c.*w3.*y./sinh(h.*w3./(kb.*T))-0.5.*c.*wc;
Irel33=c.*om033.*y./sinh(h.*om033./(kb.*T))-0.5.*c.*wc;
I33=Icm33+Irel33;
nm=1*10.^(-9);
plot(T,I1/nm,'r',T,I11/nm,'--r',T,I2/nm,'b',T,I22/nm,'--b',T,I3/nm,'k',T,I33/nm,'--k')
legend('R_1=a_B','R_1=a_B','R_2=1.2a_B','R_2=1.2a_B','R_3=1.4a_B','R_3=1.4a_B')
xlabel('T(K)')
ylabel('I (nA)')
  2 个评论
Walter Roberson
Walter Roberson 2019-9-19
h = plot(T,I1/nm,'r',T,I11/nm,'--r',T,I2/nm,'b',T,I22/nm,'--b',T,I3/nm,'k',T,I33/nm,'--k');
legend(h(1:2:end), {'R_1=a_B','R_2=1.2a_B','R_3=1.4a_B'})

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