3D plot for PDP

8 次查看(过去 30 天)
Meghashree Srikantaiah Manjesh
Hi all,
I have 29 PDP plots, each plot corresponds to different receiving angle but one tx angle. I want a 3D plot for this case, Is it possible ? please help me with generic code.
Thanks in advance
  3 个评论
Meghashree Srikantaiah Manjesh
PDP.PNG
I want to plot something like this. Instead of absolute time I want angle representation. ex: 0deg: 10deg:180deg.
tyler seudath
tyler seudath 2021-2-15
Hi, did you ever got through in plotting the 3D power delay profile?

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回答(1 个)

nathan welch
nathan welch 2020-3-6
Hopefully the following is helpful:
%just making up some data... you already have your own..
receivingAngle = 0:360;
txAngle = 10:10:180;
[receivingAngle, txAngle] = ndgrid(receivingAngle, txAngle);
PdP = exp(-(recievingAngle-txAngle).^2/100);
%notice that I have 361 receiving angles and 18 tx angles
%ndgrid replicates them with each other so they both become 361 by 18
%these are the same size (361,18) as my PdP data
%I can now use plot3
figure
plot3(receivingAngle, txAngle, PdP)
%formatting to make the plot look nice
grid on %helps visualise 3D plots
view(20,40); %give you the same angle as your plot
xlabel('receiving angle (deg)')
ylabel('tx angle (deg)')
zlabel('PDP')

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