Conversion to char from logical is not possible.

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Ludovico Iannizzotto
评论： Ludovico Iannizzotto 2020-3-29
Hi,
I am trying to solve the following integral with MATLAB_R2019b.
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i))), ['ArrayValued';true];
L = integral(I,0,Inf);
but I get the following error:
I =
function_handle with value:
@(x)((x.^(3).*exp(-x))/(x.^(3)+D(i)))
Error using vertcat
The following error occurred converting from logical to char:
Conversion to char from logical is not possible.
Error in untitled3 (line 6)
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i))), ['ArrayValued';true];
Can someone help? Thank you.
  2 个评论
Rik
Rik 2020-3-29
It looks like ['ArrayValued';true] is executed separately from the rest. It is also unclear to me what this code is supposed to be doing.
Ludovico Iannizzotto
Ludovico Iannizzotto 2020-3-29
Suppose that D(i)=7.
I am trying to solve the integral from 0-inf. However, this error arises. Do you have any suggestions on how to use ['ArrayValued';true] ??
Thanks

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采纳的回答

Rik
Rik 2020-3-29
You need to pass the option as a parameter to the integral function instead of defining it earlier.
I= @(x)((x.^(3).*exp(-x))/(x.^(3)+D(i)));
L = integral(I,0,Inf, 'ArrayValued';true);

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