I want to get 135 as output from 11122333345555566.where 2 4 6 are noise.

% Convert from long integer to vector of integers
K = 11122333345555566;   % for demo purposes
i = 1;                   % for demo purposes
noise = [2 4 6]; 
m = floor(log10(K(i)));  
v = mod(floor(K(i) ./ 10 .^ (m:-1:0)), 10);
signal = unique(v(~ismember(v,noise)), 'stable')

The lines calculating m and v are from this question.

If the number of digits in K gets too big, you'll have to use a symbolic approach that doesn't have precision limitations.

6 个评论
显示 4更早的评论隐藏 4更早的评论

Geetha K 2020-4-29

if the numbers repeating only one or two time. Then the number is noise. If the numbers repeating three or more times then that isn't noise.

Adam Danz 2020-4-29

在 MATLAB Online 中打开

That's much better.

% Demo values
K = 11122333345555566;   % for demo purposes
i = 1;                   % for demo purposes
% Convert from long integer to vector of integers
m = floor(log10(K(i)));  
v = mod(floor(K(i) ./ 10 .^ (m:-1:0)), 10);
% Detect when vector changes
isChg = diff([v(1)-1,v]);
% Count consecutive values
count = diff(find([isChg,true]));
% detect beginning of >2 consecutive values
isChg(isChg==1) = count;
sigStart = isChg >= 3; 
% Extract unique signal values 
signal = v(sigStart)