Error "Index in position 1 exceeds array bounds (must not exceed 1)" for a matrix that has a size of 2000x11

1 次查看(过去 30 天)
I am trying to write a code for generating the strain in a marticualr material. However as I am running the code I am getting the error as listed in the title for line 68 C(i,j)=(-lamda(i,j)+4*A(i,j)/3)/(Kl+4*G(i,j)/3); of the following code:
P.S timenode=2000 and spacenode =11. These are values this code is pulling from another matlab file in the same directory.
clc;
G=zeros(timenode,spacenode);
epsilonzz=zeros(timenode,spacenode);
epsilonxx=zeros(timenode,spacenode);
A=zeros(timenode,spacenode);
B=zeros(timenode,spacenode);
C=zeros(timenode,spacenode);
lamda=zeros(timenode,spacenode);
sigmaxx=zeros(timenode,spacenode);
Kl=3.5e9;
Kg=2.3e9;
syms q
q=zeros(50,1);
for j=1:spacenode
for i=1:timenode
if(T(i,j)<Tg)
q(j,1)=i;
break
end
end
end
E=2.1e9;
nu=0.38;
g=E/(2*(1+nu));
t1=0.1;
t2=100;
t3=100000;
g1=0.9944*g;
g2=0.0036*g;
g3=0.0020*g;
G=zeros(timenode,spacenode);
for j=1:spacenode
for i=2:timenode
xmin=ksi(i-1,j);
temp=ksi(i,j);
xmax=ksi(i,j);
fun1=@(x) g1*exp(-(temp-x)/t1);
fun2=@(x) g2*exp(-(temp-x)/t2);
fun3=@(x) g3*exp(-(temp-x)/t3);
val_1=integral(fun1,xmin,xmax);
val_2=integral(fun2,xmin,xmax);
val_3=integral(fun3,xmin,xmax);
G(i,j)=(val_1+val_2+val_3)/(xmax-xmin);
end
end
for i=2:timenode
for j=1:spacenode
if (i==2)
A(i,j)=-G(i,j)*(epsilonzz(i-1,j)-epsilonxx(i-1,j));
elseif (i==3)
A(i,j)=(-G(i,j)*(epsilonzz(i-1,j)-epsilonxx(i-1,j)))+(G(2,j)*(epsilonzz(2,j)-epsilonzz(1,j)-epsilonxx(2,j)+epsilonxx(i,j)));
else
tempvalue=0;
tempcounter=i-1;
for p=2:tempcounter
value=G(p,j)*(epsilonzz(p,j)-epsilonzz(p-1,j)-epsilonxx(p,j)+epsilonxx(p-1,j));
tempvalue=tempvalue+value;
end
A=(-G(i,j)*(epsilonzz(i-1,j)-epsilonxx(i-1,j)))+tempvalue;
end
B(i,j)=-(2*Kl-4*G(i,j)/3)/(Kl+4*G(i,j)/3);
if(T(i,j)>Tg)
lamda(i,j)=-3*epsilon(i,j)*Kl;
else
f=q(j,1);
lamda(i,j)=-3*Kg*epsilon(i,j)-(Kg-Kl)*(epsilonxx(f,j)+2*epsilonzz(f,j)-3*epsilon(f,j));
end
C(i,j)=(-lamda(i,j)+4*A(i,j)/3)/(Kl+4*G(i,j)/3);
end
end

采纳的回答

dpb
dpb 2020-7-10
A=(-G(i,j)*(epsilonzz(i-1,j)-epsilonxx(i-1,j)))+tempvalue;
You just redefined the whole array A to the RHS consisting of a single element for all i,j

更多回答(1 个)

Matt J
Matt J 2020-7-10
编辑:Matt J 2020-7-10
I am getting the error as listed in the title for line 68 C(i,j)=(-lamda(i,j)+4*A(i,j)/3)/(Kl+4*G(i,j)/3); of the following code:
You should pause the code at that line when the error occurs and examine the state of the variables there. What is the size of all the variables on the RHS? And what are the values of i and j?

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

产品


版本

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by