what y(2) ,y(3), y(4) , y(5) ,by using matlab ?

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majed alharbi
majed alharbi 2020-9-19
评论： Rena Berman 2020-10-8
y(0)=1 y(2)=5
y(n+2)=3y(n+1)-5y(n)
what y(2) ,y(3), y(4) , y(5) ,by using matlab ?
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Stephen23
Stephen23 2020-9-19
Original question by majed alharbi retrieved from Google Cache:
"what y(2) ,y(3), y(4) , y(5) ,by using matlab ?"
y(0)=1 y(2)=5
y(n+2)=3y(n+1)-5y(n)
what y(2) ,y(3), y(4) , y(5) ,by using matlab ?

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回答（1 个）

Alan Stevens
Alan Stevens 2020-9-19
You need to start with y(1) = 1, not y(0) = 1. Then with y(2) = 5, you can use a for loop:
for n=1:3, y(n+2) = 3*y(n+1)-5*y(n); end
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Walter Roberson
Walter Roberson 2020-9-19
编辑：Walter Roberson 2020-9-19
you did not loop like I suggested. You tried to vectorize.
The function can only be vectorized after a bunch of mathematical calculations to figure out the general form. I recommend looping, it is much easier.

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