How to avoid the rounding off of data ?

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Mahesh Babu Dhanekula
评论： Steven Lord 2020-9-30
I am trying to perform the following divison operation.
l = 2.093750000000000e+09;
l/10^9
It was giving the output as:
ans =
2.0938
But i need the output as 2.09375 only. How an i achieve it ? I want to use it in further calculations as 2.09375 only. Is there any way to achieve this ?
l = 2.187500000000000e+09;
l/10^9
This was giving desired output in this case.
ans =
2.1875
If anybody knows how to solve this, please share your thoughts.

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回答（1 个）

Arthur Roué
Arthur Roué 2020-9-30
编辑：Arthur Roué 2020-9-30
There is no problem here, the default display format is set to short. Try :
format long
l = 2.093750000000000e+09;;
l/10^9
ans =
2.093750000000000
You can also access to the variable with the variable inspector : just double click on your variable in the workspace explorer.
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Mahesh Babu Dhanekula
Mahesh Babu Dhanekula 2020-9-30
Thanks for reading my 2 questions. This is exactly what i needed steven.
I have a number 2.093750000000000e+09, and I want to to covert this into 2.09375Hz. So how can i do this ?
If there is any way, please let me know steven
Steven Lord
Steven Lord 2020-9-30
Use fprintf or num2str to create a string or char vector with the desired format then concatenate it with the string "Hz" using +.

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