Unable to perform assignment because the left side is 1-by-3 and the right side is 1-by-2

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Colton Rippey 2020-10-21

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https://ww2.mathworks.cn/matlabcentral/answers/620788-unable-to-perform-assignment-because-the-left-side-is-1-by-3-and-the-right-side-is-1-by-2

评论： Star Strider 2020-10-21

采纳的回答： Star Strider

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Hello!

I am still struggling with trying to make graphs with categorical variables and error bars.

I am getting an error in line 11 (starts with ctr) that says "Unable to perform assignment because the left side is 1-by-3 and the right side is 1-by-2".

Am I missing a blatant 1-by-3 vector and how do I fix it without ruining my code? I apprieciate any help I can get, as I started learning Matlab just this year. Thanks!!

Here is my current code:

xc = categorical({'PTSD-','PTSD+'});
x = 1:numel(xc);
y = [.09 .13 ; -.08 -.35];
hBar = bar(x,y);
pos = [.1 .15 .2 .21];
neg = pos
posr = reshape(pos, 2, [2]);
negr = reshape(neg, 2, [2]);
for k1 = 1:size(y,2)
    ctr(k1,:) = bsxfun(@plus, 1:numel(hBar(k1).XData), hBar(k1).XOffset'); 
    ydt(k1,:) = hBar(k1).YData;
end
set(gca, 'XTick',x, 'XTickLabel',xc,'FontSize',12, 'FontName', 'Helvetica')
ylabel("Overall Cognitive Functioning (Z-Score)", 'FontSize',12, 'FontName', 'Helvetica')
ylim([-.5 .5]);
yticks([-.5, -.4 -.3 -.2 -.1 0 .1 .2 .3 .4 .5])
legend('location','northeast')
legend('FontName', 'Helvetica', 'FontSize',12)
legend boxoff
box off
legend boxoff
newcolors = ['#CBCBCB'; '#0033A0']
colororder(newcolors)
legend({'Met-','Met+'})
set(gca, 'XTick',x, 'XTickLabel',xc,'FontSize',12, 'FontName', 'Helvetica')

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Answer 1

Star Strider 2020-10-21

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https://ww2.mathworks.cn/matlabcentral/answers/620788-unable-to-perform-assignment-because-the-left-side-is-1-by-3-and-the-right-side-is-1-by-2#answer_519783

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I’m not certain what you’re doing with that line.

The standard way of coding it (to put errorbar objects or text objects at the top of the bars) is:

ctr(k1,:) = bsxfun(@plus, hBar(k1).XData, hBar(k1).XOffset')

I suspect that diference could be the problem, however I find it a bit difficult to follow your code, because I don’t see that you use ‘ctr’ or ‘ydt’ anywhere else.