How to make a single array of values from multiple different arrays one after the other

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Claire
Claire 2021-2-16
评论： Claire 2021-2-18
Hello!
I have one array, A, with serial dates from a range of dates and the same time for each date, so like for every day of one month in one year at 1:30 AM. I have another array, B, with serial dates of that same date range from that same month and year at a different time but all at 4:30 PM instead. I have another array C, with the same date range but at 11:30 pm. I want to combine all these arrays into one so that they are one large array with the dates and times in order which would be one value from A then another from B, then the next from C, then the next from A, and so on like A B C A B C A B C...
Sorry if this was unclear, thank you!
  2 个评论
Claire
Claire 2021-2-16
编辑：Claire 2021-2-18
Here is a sample of my arrays:
A B C
736055.063 736055.521 736055.896
736056.063 736056.521 736056.896
736057.063 736057.521 736057.896
I would like to combine them into one array that would look something like this:
Full array (serial date from A, followed by serial date from B, followed by serial date from C, on repeat until it is the length of the 3 arrays combined)
736055.063 A
736055.521 B
736055.896 C
736056.063 A
736056.521 B
736056.896 C
736057.063 A
736057.521 B
736057.896 C
edit: example of desired, full array was incorrect, now fixed!

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采纳的回答

KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-17
You canot combine numeric and strings together in an Array, You may do the same using cell array. Another way using table
A=[736055.063,736056.063,736057.063];
B=[736055.521,736056.521,736057.521];
C=[736055.896,736056.896,736057.896];
data=[A',B',C'];
dat=data(:);
cate=['A','B','C']';
r=length(dat)/length(cate);
col2=repmat(cate,[r,1]);
t=table(dat,col2)
Result:
t =
9×2 table
dat col2
__________ ____
736055.063 A
736056.063 B
736057.063 C
736055.521 A
736056.521 B
736057.521 C
736055.896 A
736056.896 B
736057.896 C
  2 个评论
KALYAN ACHARJYA
KALYAN ACHARJYA 2021-2-18
编辑：KALYAN ACHARJYA 2021-2-18
Here:
A=[736055.063,736056.063,736057.063];
B=[736055.521,736056.521,736057.521];
C=[736055.896,736056.896,736057.896];
data=reshape([A;B;C],size(A,1),[]);
dat=data(:);
cate=['A','B','C']';
r=length(dat)/length(cate);
col2=repmat(cate,[r,1]);
t=table(dat,col2)
Result:
t =
9×2 table
dat col2
__________ ____
736055.063 A
736055.521 B
736055.896 C
736056.063 A
736056.521 B
736056.896 C
736057.063 A
736057.521 B
736057.896 C

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