ranking the data in matrix and arrange them as per rank.

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Karanvir singh Sohal
评论： Bruno Luong 2021-4-4
Hello!
I have a matrix D and E
D=[1 2 3; 7 8 9; 4 5 6; 3 0 5];
E=[D sum(D')' ranks(sum(D')')]
output of E is
E = [ 1 2 3 6 1
7 8 9 24 4
4 5 6 15 3
3 0 5 8 2]
Ok now I have 2 doubts
  1. I want to rank(last column of E) in a way that highest(24) value in column 4 gets rank 1.
  2. I want sort the data in another matrix such that rank 1 row gets on top.
expected results
[7 8 9 24 1
4 5 6 15 2
3 0 5 8 3
1 2 3 6 4]

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采纳的回答

Bruno Luong
Bruno Luong 2021-4-4
>> D=[1 2 3; 7 8 9; 4 5 6; 3 0 5];
E=[D sum(D')' ranks(sum(D')')]
Unrecognized function or variable 'ranks'.
Did you mean:
>> E=[D sum(D')']
E =
1 2 3 6
7 8 9 24
4 5 6 15
3 0 5 8
>> sortrows(E,-4)
ans =
7 8 9 24
4 5 6 15
3 0 5 8
1 2 3 6
I let youu deal with the last column, that is nothing more or less interesting than the row index of the array
  2 个评论
Karanvir singh Sohal
Karanvir singh Sohal 2021-4-4
Great it works as per my requirement for sorting rows.
Can you please tell how to rank? Like row with highest sum will have rank 1.
[25 1
15 2
8 3
6 4]
Bruno Luong
Bruno Luong 2021-4-4
as I said rank after sorting is
r = (1:size(D,1))'
It's a row index of your sorted array.

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