Working with cells of letters

3 次查看(过去 30 天)
Craig
Craig 2013-9-16
Hi all,
I have a cell (1 by X) containing various other cells of letters. I would like to create a loop (X is a variable) which "extracts" each cell from the main cell AND converts it to a double. Can this be done?
Having issues achieving this as MATLAB doesn't seem to enjoy working with letters!
Craig
[EDITED, Jan, copied from comment section]
X= {{'AB';'AC';'AE':'AD'},{'ABC';'ACD'},{'ABED';'ABCD';'AEFD';'ADFG'},{'ABCDEFG'}};
I want to extract all cells from X and convert each to a double.
  2 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2013-9-16
Post a sample of your data.
Jan
Jan 2013-9-17
@Craig: Please post all required information inside the question. Comments run out of view, if other comments are posted later.

请先登录,再进行评论。

回答(2 个)

Sean de Wolski
Sean de Wolski 2013-9-16
So:
cellfun(@str2double,{{'1','3','34'},{'45'},{'12','1017'}},'uni',false)
  5 个评论
Craig
Craig 2013-9-17
That is currently what I am thinking I will have to do. Not sure how to convert a whole cell to ascii values though.
Sean de Wolski
Sean de Wolski 2013-9-17
double('A')
Rather than string to double which interprets the value not the ascii. What is your big picture here, what are you trying to do?

请先登录,再进行评论。


Jan
Jan 2013-9-17
编辑:Jan 2013-9-17
'A' cannot be converted to a double, because it is a letter. The same matters your 'AB', 'ABC', etc also. So please explain, what you expect as output.
You have recognized this problem already: "MATLAB doesn't seem to enjoy working with letters". But as long as such operations are not defined, how could we or Matlab know, what you are trying to do?
  4 个评论
Craig
Craig 2013-9-17
编辑:Craig 2013-9-17
Say I have, x=
'A' 'B' 'D'
'A' 'B' 'E'
'A' 'B' 'F'
'A' 'B' 'G'
'A' 'B' 'H'
'A' 'B' 'I'
'A' 'B' 'J'
'A' 'B' 'K'
'A' 'B' 'L'
'A' 'B' 'M'
'A' 'C' 'D'
'A' 'C' 'E'
And pairs of letters, y=
'A' 'C'
'E' 'D'
'E' 'C'
'J' 'I'
'J' 'H'
'M' 'L'
'V' 'T'
'V' 'U'
'Q' 'N'
'Q' 'O'
'Q' 'P'
So I want to loop through each row of y with x so it returns a "new x" =
'A' 'B' 'D'
'A' 'B' 'E'
'A' 'B' 'F'
'A' 'B' 'G'
'A' 'B' 'H'
'A' 'B' 'I'
'A' 'B' 'J'
'A' 'B' 'K'
'A' 'B' 'L'
'A' 'B' 'M'
Where some rows have been removed as they contain both letters contained in any row of y.
Thanks for helping out. It is hard to explain.
Jan
Jan 2013-9-17
This is still not valid Matlab syntax:
x=
'A' 'B' 'D'
'A' 'B' 'E'
...
The details matter. So please post code, which we can run by copy&paste.
In "new x" (better use a valid Matlab name here also) the contents of "x" has been modified and some rows are removed. But there is an infinite number of possible algorithms to convert "x" to "new x". Then it is not clear, if you have managed to solve the procedure shown in the comment or if this belongs to the problem.
The only line of code or sentence I understand from your question yet is:
X = {{'AB';'AC';'AE':'AD'},{'ABC';'ACD'},{'ABED';'ABCD';'AEFD';'ADFG'},{'ABCDEFG'}};
Unfortunately I do not see any relation to e.g. your above comment or the text of the original question.
Craig, I know problems are hard to explain. It seems like the the level of abstraction is too high to allow a clear explanation. So try to solve the problem from another direction: Explain the actual problem you want to solve by this method.

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Matrix Indexing 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by