Curve fitting and scatter plots

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Hi all,
This may not be possible but is there a function or a way you can fit a curve to a select number of points within a scatterplot? Looking specifically to fit a curve around the 'lower boundary' of a scatterplot. For example say I had a scatterplot of hundreds of points that made up a circle. Is there a way to fit a curve around the bottom perimeter?
If you need any more info please ask.
Best
  1 个评论
dpb
dpb 2013-9-22
How do you define what is the "bottom perimeter", specifically?
One (probably crude) choice would be to pick all values in the data set whose y-values<=mean(y)

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采纳的回答

Image Analyst
Image Analyst 2013-11-22
Craig, try this to see if it's what you want. I create a bunch of noisy points around a circle. Then I select the bottom half of those. Then I fit a circle through the points, using only those points in the bottom half of the circle to determine the fitted equation. I think that's what you've been saying you want. Save the following in test.m and run it.
function test
clc; % Clear the command window.
workspace; % Make sure the workspace panel is showing.
format long g;
format compact;
fontSize = 20;
xCenter = 12;
yCenter = 10;
theta = 0 : 0.01 : 2*pi;
radius = 5 + 2*rand(1, length(theta));
x = radius .* cos(theta) + xCenter;
y = radius .* sin(theta) + yCenter;
plot(x, y, 'b*');
axis square;
xlim([0 20]);
ylim([0 20]);
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% Get the bottom half of them
selector = y < yCenter;
bottomHalfY = y(selector);
bottomHalfX = x(selector);
hold on;
plot(bottomHalfX, bottomHalfY, 'ro');
% Fit a circle to the bottom half noisy data:
[xc,yc,R,a] = circfit(x,y)
xFit = R .* cos(theta) + xc;
yFit = R .* sin(theta) + yc;
plot(xFit, yFit, 'r-', 'LineWidth', 3);
function [xc,yc,R,a] = circfit(x,y)
%CIRCFIT Fits a circle in x,y plane
% http://matlab.wikia.com/wiki/FAQ#How_can_I_fit_a_circle_to_a_set_of_XY_data.3F
% [XC, YC, R, A] = CIRCFIT(X,Y)
% Result is center point (yc,xc) and radius R. A is an optional
% output describing the circle's equation:
%
% x^2+y^2+a(1)*x+a(2)*y+a(3)=0
% by Bucher izhak 25/oct/1991
n=length(x); xx=x.*x; yy=y.*y; xy=x.*y;
A=[sum(x) sum(y) n;sum(xy) sum(yy) sum(y);sum(xx) sum(xy) sum(x)];
B=[-sum(xx+yy) ; -sum(xx.*y+yy.*y) ; -sum(xx.*x+xy.*y)];
a=A\B;
xc = -.5*a(1);
yc = -.5*a(2);
R = sqrt((a(1)^2+a(2)^2)/4-a(3));
  3 个评论
Image Analyst
Image Analyst 2013-11-23
编辑:Image Analyst 2013-11-24
Assuming you have xData and yData, try this:
counter = 1;
for x = 0 : 10 : 100
x1 = x;
x2 = x1 + 10;
indexes = xData > x1 & xData < x2;
minY(counter) = min(y(indexes));
counter = counter + 1;
end
Now minY has the min y value for each segment 0-10, 10-20, 20-30, etc.
Craig
Craig 2013-11-24
You are good. :) thanks alot.

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更多回答(2 个)

Image Analyst
Image Analyst 2013-9-22
If you know the indexes of those points, then, sure. Just put the arrays with those indexes into polyfit() or whatever you're using.

SCADA Miner
SCADA Miner 2013-11-13
Hi Craig, Did you ever figure out how to do this? I want to do the same thing. I have a bunch of measurements which form a scatter plot, I want to fit a curve which is the lower bound for say 95% of those points. I can think of a really inefficient way to do it but surely something already exists? Cheers Tom
  3 个评论
Craig
Craig 2013-11-22
I think the difficulty is I am working with a scatter plot containing upwards of 200,000 data points meaning my polynomial could be over order 10 or higher. I am not too familiar with polyfit. Could you explain how I could use it here?
dpb
dpb 2013-11-22
The polynomial is only of the order you select.
Fit the data; if there's any way to know a priori to subset it at least some beforehand that would be a_good_thing (tm) but not mandatory. Then evaluate the result over the same fitted range, compute the residuals and as IA says, find the smallest group. You could then selectively refit those to improve the fit w/o the others polluting the estimates.
See
doc polyfit % and friends for more details

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