{"group":{"id":1,"name":"Community","lockable":false,"created_at":"2012-01-18T18:02:15.000Z","updated_at":"2026-05-26T00:16:20.000Z","description":"Problems submitted by members of the MATLAB Central community.","is_default":true,"created_by":161519,"badge_id":null,"featured":false,"trending":false,"solution_count_in_trending_period":0,"trending_last_calculated":"2026-05-26T00:00:00.000Z","image_id":null,"published":true,"community_created":false,"status_id":2,"is_default_group_for_player":false,"deleted_by":null,"deleted_at":null,"restored_by":null,"restored_at":null,"description_opc":null,"description_html":null,"published_at":null},"problems":[{"id":2104,"title":"construct matrix with identical rows","description":"Input a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x. \r\n\r\nExample \r\n\r\n L = 5\r\n\r\nThe resulting answer is:\r\n\r\n [1:10;\r\n  1:10;\r\n  1:10; \r\n  1:10;\r\n  1:10]\r\n\r\n","description_html":"\u003cp\u003eInput a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x.\u003c/p\u003e\u003cp\u003eExample\u003c/p\u003e\u003cpre\u003e L = 5\u003c/pre\u003e\u003cp\u003eThe resulting answer is:\u003c/p\u003e\u003cpre\u003e [1:10;\r\n  1:10;\r\n  1:10; \r\n  1:10;\r\n  1:10]\u003c/pre\u003e","function_template":"function c=consIdenticalRowMatrix(a,rows)\r\n%you code here\r\nend\r\n","test_suite":"%%\r\nx = [1:10];\r\ny_correct =[1:10;1:10];\r\nrows=2;\r\nassert(isequal(consIdenticalRowMatrix(x,rows),y_correct))\r\n\r\nx=1:5;\r\nrows=5;\r\ny_correct=[x;x;x;x;x];\r\nassert(isequal(consIdenticalRowMatrix(x,rows),y_correct))","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":9153,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":209,"test_suite_updated_at":"2014-06-25T08:39:31.000Z","rescore_all_solutions":true,"group_id":1,"created_at":"2014-01-11T10:17:53.000Z","updated_at":"2026-02-08T06:10:56.000Z","published_at":"2014-01-11T10:17:53.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eInput a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ L = 5]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe resulting answer is:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ [1:10;\\n  1:10;\\n  1:10; \\n  1:10;\\n  1:10]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"problems":[{"id":2104,"title":"construct matrix with identical rows","description":"Input a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x. \r\n\r\nExample \r\n\r\n L = 5\r\n\r\nThe resulting answer is:\r\n\r\n [1:10;\r\n  1:10;\r\n  1:10; \r\n  1:10;\r\n  1:10]\r\n\r\n","description_html":"\u003cp\u003eInput a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x.\u003c/p\u003e\u003cp\u003eExample\u003c/p\u003e\u003cpre\u003e L = 5\u003c/pre\u003e\u003cp\u003eThe resulting answer is:\u003c/p\u003e\u003cpre\u003e [1:10;\r\n  1:10;\r\n  1:10; \r\n  1:10;\r\n  1:10]\u003c/pre\u003e","function_template":"function c=consIdenticalRowMatrix(a,rows)\r\n%you code here\r\nend\r\n","test_suite":"%%\r\nx = [1:10];\r\ny_correct =[1:10;1:10];\r\nrows=2;\r\nassert(isequal(consIdenticalRowMatrix(x,rows),y_correct))\r\n\r\nx=1:5;\r\nrows=5;\r\ny_correct=[x;x;x;x;x];\r\nassert(isequal(consIdenticalRowMatrix(x,rows),y_correct))","published":true,"deleted":false,"likes_count":2,"comments_count":0,"created_by":9153,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":209,"test_suite_updated_at":"2014-06-25T08:39:31.000Z","rescore_all_solutions":true,"group_id":1,"created_at":"2014-01-11T10:17:53.000Z","updated_at":"2026-02-08T06:10:56.000Z","published_at":"2014-01-11T10:17:53.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eInput a row vector such as x=1:10. Now we need to construct a matrix with L rows,of which every row vector is a copy of x.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eExample\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ L = 5]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThe resulting answer is:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"code\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e\u003c![CDATA[ [1:10;\\n  1:10;\\n  1:10; \\n  1:10;\\n  1:10]]]\u003e\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"errors":[],"facets":[[],[{"value":"easy","count":1,"selected":false}]],"term":"tag:\"construct identical row matrix\"","page":1,"per_page":50,"sort":"map(difficulty_value,0,0,999) asc"}}