Improve Model Fit with Weights
This example shows how to fit a polynomial model to data using both the linear least-squares method and the weighted least-squares method for comparison.
Generate sample data from different normal distributions by using the randn
function.
rng("default") % For reproducibility rnorm = []; idx = []; for k=1:20 r = k*randn([20,1]) + (1/20)*(k^3); rnorm = [rnorm;r]; idx = [idx;ones(20,1).*k]; end
The dependent variable rnorm
contains sample data from 20 normal distributions. The independent variable idx
contains integers indicating whether two elements in rnorm
are sampled from the same normal distribution.
Fit a third-degree polynomial model to idx
and rnorm
. Return information about the coefficient estimates and the algorithm used to fit the model.
[p3fit,~,fitinfo] = fit(idx,rnorm,"poly3")
p3fit = Linear model Poly3: p3fit(x) = p1*x^3 + p2*x^2 + p3*x + p4 Coefficients (with 95% confidence bounds): p1 = 0.05156 (0.0438, 0.05932) p2 = -0.03993 (-0.2875, 0.2076) p3 = 0.1418 (-2.124, 2.408) p4 = 0.0462 (-5.585, 5.678)
fitinfo = struct with fields:
numobs: 400
numparam: 4
residuals: [400x1 double]
Jacobian: [400x4 double]
exitflag: 1
algorithm: 'QR factorization and solve'
iterations: 1
p3fit
contains the estimates for the model coefficients with 95% confidence intervals. The default fitting method for fitting a polynomial model is linear least squares. fitinfo
contains information about the fitting algorithm used to fit the coefficients to the data. The error in the data can be estimated by the residuals stored in fitinfo
.
Plot the residuals using a stem plot.
stem(idx,fitinfo.residuals) xlabel("idx") ylabel("residuals")
The plot of the residuals shows that their variance increases as the values in idx
increase. The nonconstant variances across the different values of idx
indicate that the weighted least-squares fitting method is more appropriate for calculating the model coefficients.
Create a vector of zeros for later storage of the weights.
W = zeros(length(rnorm),1);
The weights you supply transform the residual variances so that they are constant for different values of idx
. Define the weight for each element in rnorm
as the reciprocal of the residual variance for the corresponding value in idx
. Then fit the model with the weights.
for k=1:20 rnorm_idx = rnorm(idx==k); recipvar = 1/var(rnorm_idx); w = (idx==k).*recipvar; W = W+w; end [wp3fit,~,wfitinfo] = fit(idx,rnorm,"poly3","Weights",W)
wp3fit = Linear model Poly3: wp3fit(x) = p1*x^3 + p2*x^2 + p3*x + p4 Coefficients (with 95% confidence bounds): p1 = 1.443 (1.383, 1.504) p2 = -13.36 (-14.56, -12.15) p3 = 36.59 (31.4, 41.78) p4 = -24.23 (-29.15, -19.31)
wfitinfo = struct with fields:
numobs: 400
numparam: 4
residuals: [400x1 double]
Jacobian: [400x4 double]
exitflag: 1
algorithm: 'QR factorization and solve'
iterations: 1
wp3fit
and wfitinfo
contain the results of the weighted least-squares fitting.
Display p3fit
, wp3fit
, and rnorm
in the same plot.
plot(p3fit,idx,rnorm) hold on plot(wp3fit,"g") xlabel("idx") ylabel("rnorm") legend(["rnorm","linear least-squares fit","weighted least-squares fit"]) hold off
The plot shows wp3fit
closely tracking p3fit
.
You can determine whether wp3fit
is a better fit than p3fit
by plotting the residuals.
stem(idx,wfitinfo.residuals) xlabel("idx") ylabel("residuals")
The output shows that the wp3fit
residuals are smaller than the p3fit
residuals. The variances of the wp3fit
residuals are also more similar for different values of idx
than the variances of the p3fit
residuals.