circcirc

Find intersection of circles in Cartesian coordinates

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Syntax

[xout,yout] = circcirc(centerx1,centery1,radius1,centerx2,centery2,radius2)

Description

[xout,yout] = circcirc(centerx1,centery1,radius1,centerx2,centery2,radius2) finds the intersection of two circles with the specified centers and radii, in Cartesian coordinates.

example

Examples

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Open Live Script

Find the intersection of two circles. The first circle has its center at (–2, 3) and a radius of 4. The second circle has its center at (1, –5) and a radius of 6.

[xout,yout] = circcirc(-2,3,4,1,-5,6)
xout = 1×2

    1.4541   -3.2760


yout = 1×2

    0.9828   -0.7910

Input Arguments

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x-coordinate of the center of the first circle, specified as a numeric scalar.

y-coordinate of the center of the first circle, specified as a numeric scalar.

Radius of the first circle, specified as a positive scalar.

x-coordinate of the center of the second circle, specified as a numeric scalar.

y-coordinate of the center of the second circle, specified as a numeric scalar.

Radius of the second circle, specified as a positive scalar.

Output Arguments

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x-coordinates of the intersections, returned as a two-element vector.

  • When the circles are tangent, the elements of the vector are equal.

  • When the circles do not intersect or are identical, both elements are NaN.

y-coordinates of the intersections, returned as a two-element vector.

  • When the circles are tangent, the elements of the vector are equal.

  • When the circles do not intersect or are identical, both elements are NaN.

Version History

Introduced before R2006a

See Also

Functions