getFaultInfoFile

Get name of fault information file

Since R2023b

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Syntax

name = getFaultInfoFile(fault)

Description

name = getFaultInfoFile(fault) returns the name of the fault information file associated with the fault, fault.

example

Examples

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Open a model with a block that supports fault modeling.

openExample("simscape_shared/SimpleMotorArmatureWindingFaultExample")

Add a fault to the DC Motor block.

myFault = Simulink.fault.addFault(...
"SimpleMotorArmatureWindingFault/DC Motor/Armature winding");

Retrieve the name of the fault information file associated with the fault.

myInfoFile = getFaultInfoFile(myFault)
myInfoFile = getFaultInfoFile(myFault)

myInfoFile =

    'SimpleMotorArmatureWindingFault_faultInfo.xml'

Input Arguments

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Fault, specified as a Fault object.

Output Arguments

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Name of the fault information file associated with the fault, returned as a character vector.

Version History

Introduced in R2023b

See Also

Objects

Functions