powermod

Modular exponentiation

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Syntax

c = powermod(a,b,m)

Description

c = powermod(a,b,m) returns the modular exponentiation ab mod m. The input a,b must be integers, and m must be a nonnegative integer. For more information, see Modular Exponentiation.

example

Examples

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Compute the modular exponentiation ab mod m by using powermod. The powermod function is efficient because it does not calculate the exponential ab.

c = powermod(3,5,7)
c =
     5

Fermat's little theorem states that if p is prime and a is not divisible by p, then a(p–1) mod p is 1.

Test Fermat's little theorem for p = 5, a = 3. As expected, powermod returns 1.

p = 5;
a = 3;
c = powermod(a,p-1,p)
c =
1

Test the same case for all values of a less than p. The function powermod acts element-wise to return a vector of ones.

p = 5;
a = 1:p-1;
c = powermod(a,p-1,p)
c =
     1     1     1     1

Fermat's little theorem states that if p is a prime number and a is not divisible by p, then a(p–1) mod p is 1. On the contrary, if a(p–1) mod p is 1 and a is not divisible by p, then p is not always a prime number (p can be a pseudoprime).

Test numbers from 300 to 400 for primality by using Fermat's little theorem with base 2.

p = 300:400;
remainder = powermod(2,p-1,p);
primesFermat = p(remainder == 1)
primesFermat =
   307   311   313   317   331   337   341   347   349   353...
   359   367   373   379   383   389   397

Find Fermat pseudoprimes by comparing the results with isprime. 341 is a Fermat pseudoprime.

primeNumbers = p(isprime(p));
setdiff(primesFermat,primeNumbers)
ans =
   341

Input Arguments

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Base, specified as a number, vector, matrix, array, or a symbolic number or array. a must be an integer.

Exponent or power, specified as a number, vector, matrix, array, or a symbolic number or array. b must be an integer.

Divisor, specified as a number, vector, matrix, array, or a symbolic number or array. m must be a nonnegative integer.

More About

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Version History

Introduced in R2018a

See Also

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