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wlanHTLTF

Generate HT-LTF waveform

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Syntax

y = wlanHTLTF(cfg)
y = wlanHTLTF(cfg,OversamplingFactor=osf)

Description

y = wlanHTLTF(cfg) generates an HT-LTF1 time-domain waveform for HT-mixed transmissions with parameters specified in cfg.

example

y = wlanHTLTF(cfg,OversamplingFactor=osf) generates an oversampled HT-LTF waveform with the specified oversampling factor.

example

Examples

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Open Live Script

Create a wlanHTConfig object having a channel bandwidth of 40 MHz.

cfg = wlanHTConfig('ChannelBandwidth','CBW40');

Generate the corresponding HT-LTF.

hltfOut = wlanHTLTF(cfg);
size(hltfOut)
ans = 1×2

   160     1

The cfg parameters result in a 160-sample waveform having only one column corresponding to a single stream transmission.

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Generate an oversampled HT-LTF waveform with four transmit antennas and four space-time streams.

Create a wlanHTConfig configuration with MCS index 31, four transmit antennas, and four space-time streams.

cfg = wlanHTConfig('MCS',31,'NumTransmitAntennas',4,'NumSpaceTimeStreams',4)
cfg = 
  wlanHTConfig with properties:

       ChannelBandwidth: 'CBW20'
    NumTransmitAntennas: 4
    NumSpaceTimeStreams: 4
         SpatialMapping: 'Direct'
                    MCS: 31
          GuardInterval: 'Long'
          ChannelCoding: 'BCC'
             PSDULength: 1024
         AggregatedMPDU: 0
     RecommendSmoothing: 1

Specify an oversampling factor and generate the corresponding HT-LTF waveform.

osf = 4;
y = wlanHTLTF(cfg,OversamplingFactor=osf);

Verify that the waveform output consists of four streams (one for each antenna). Because the channel bandwidth is 20 MHz and the waveform is oversampled and has four space-time streams, the waveform has four HT-LTF and 1280 time-domain samples.

size(y)
ans = 1×2

        1280           4

Input Arguments

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Transmission parameters, specified as a wlanHTConfig object.

Oversampling factor, specified as a scalar greater than or equal to 1. The oversampled cyclic prefix length must be an integer number of samples.

Data Types: single | double | int8 | int16 | int32 | int64 | uint8 | uint16 | uint32 | uint64

Output Arguments

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HT-LTF waveform, returned as an (NS × NHTLTF)-by-NT matrix. NS is the number of time domain samples per NHTLTF, where NHTLTF is the number of OFDM symbols in the HT-LTF. NT is the number of transmit antennas.

NS is proportional to the channel bandwidth. Each symbol contains 80 time samples per 20 MHz channel.

ChannelBandwidthNS
'CBW20'80
'CBW40'160

Determination of the number of NHTLTF is described in HT-LTF.

Data Types: double
Complex Number Support: Yes

More About

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HT-LTF

The high throughput long training field (HT-LTF) is located between the HT-STF and data field of an HT-mixed packet.

As described in Section 19.3.9.4.6 of IEEE® Std 802.11™-2016, the receiver can use the HT-LTF to estimate the MIMO channel between the set of QAM mapper outputs (or, if STBC is applied, the STBC encoder outputs) and the receive chains. The HT-LTF portion has one or two parts. The first part consists of one, two, or four HT-LTFs that are necessary for demodulation of the HT-Data portion of the PPDU. These HT-LTFs are referred to as HT-DLTFs. The optional second part consists of zero, one, two, or four HT-LTFs that can be used to sound extra spatial dimensions of the MIMO channel not utilized by the HT-Data portion of the PPDU. These HT-LTFs are referred to as HT-ELTFs. Each HT long training symbol is 4 μs. The number of space-time streams and the number of extension streams determines the number of HT-LTF symbols transmitted.

Tables 19-12, 19-13 and 90-14 from IEEE Std 802.11-2012 are reproduced here.

NSTS DeterminationNHTDLTF DeterminationNHTELTF Determination

Table 19-12 defines the number of space-time streams (NSTS) based on the number of spatial streams (NSS) from the MCS and the STBC field.

Table 19-13 defines the number of HT-DLTFs required for the NSTS.

Table 19-14 defines the number of HT-ELTFs required for the number of extension spatial streams (NESS). NESS is defined in HT-SIG2.

NSS from MCSSTBC fieldNSTS
101
112
202
213
224
303
314
404

NSTSNHTDLTF
11
22
34
44

NESSNHTELTF
00
11
22
34

Additional constraints include:

  • NHTLTF = NHTDLTF + NHTELTF ≤ 5.

  • NSTS + NESS ≤ 4.

    • When NSTS = 3, NESS cannot exceed one.

    • If NESS = 1 when NSTS = 3 then NHTLTF = 5.

HT-mixed

As described in IEEE Std 802.11-2012, Section 20.1.4, high throughput mixed (HT-mixed) format packets contain a preamble compatible with IEEE Std 802.11-2012, Section 18 and Section 19 receivers. Non-HT (Section 18 and Section19) STAs can decode the non-HT fields (L-STF, L-LTF, and L-SIG). The remaining preamble fields (HT-SIG, HT-STF, and HT-LTF) are for HT transmission, so the Section 18 and Section 19 STAs cannot decode them. The HT portion of the packet is described in IEEE Std 802.11-2012, Section 20.3.9.4. Support for the HT-mixed format is mandatory.

PPDU

The physical layer (PHY) protocol data unit (PPDU) is the complete physical layer convergence procedure (PLCP) frame, including PLCP headers, MAC headers, the MAC data field, and the MAC and PLCP trailers.

References

[1] IEEE Std 802.11™-2012 IEEE Standard for Information technology — Telecommunications and information exchange between systems — Local and metropolitan area networks — Specific requirements — Part 11: Wireless LAN Medium Access Control (MAC) and Physical Layer (PHY) Specifications.

Extended Capabilities

C/C++ Code Generation
Generate C and C++ code using MATLAB® Coder™.

Version History

Introduced in R2015b

See Also

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1 IEEE Std 802.11-2012 Adapted and reprinted with permission from IEEE. Copyright IEEE 2012. All rights reserved.