How do i get past the dimension mismatch on line 36?

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Daisy
Daisy 2013-10-31
评论： Daisy 2013-11-4
L = 0.64; % length of string (m)
T = 122; % tensile force of the string (N)
S=pi/(4e-6); % section of the string
rho = 7.8e6; % mass per unit length of string (kg/m)
c = sqrt(T/rho*S); % wave velocity (m/s)
%t = 1.3; % current time value (s)
xo = L/2; % initial displacement value (m)
% range variables
x = linspace(0,L,1000); % position points on string (m)
n = 1:numel(x); % integers for Fourier series
% pic=length(n)
% poc=length(x)
t = linspace(0,1.3,1000); %current time value (s)
%n = linspace(1,length(x),length(x)); % integers for Fourier series
v = zeros(length(n),length(x)); %tranverse displacement
pac=length(v)
h=4; % height of the string when plucked
part=((2.*(h.*L.^2))./((pi).^2.*n.^2*xo*(L-xo)));% Furier coefficient split
b= part.*sin((n.*pi*xo)./L); % the other half of Fourier coeeficient
w = n.*(pi./L); %angular velocity
for i = 1:length(x)
for j = 1:length(n)
for k=0:length(t)
% v(i,j) = v(i,j)+ % sin(n(j)*pi.*x(i)./L).*cos(c.*n(j).*pi*t./L).*b(j)
half = b(j).*(sin(w(j).*x(i)).*cos(w(j).*c.*t)) %equation split
v(i,j) = v(i,j)+ half;
end
end
end

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采纳的回答

Laurent
Laurent 2013-10-31
The problem is with your calculation of 'half'. It uses the variable 't', which is an array (1x1000) and therefore 'half' will be also (1x1000). I think you want 'half' in the line afterwards to be a scalar, so either change the way you calculate 'half', or pick one value from 'half' in the line where you calculate v(i,j).

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