why its giving error? Its saying cant read A1(2.3), its not logical

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Rizwana
Rizwana 2013-11-7
评论： Rizwana 2013-11-7
t = 1:9;
t1 = 1 : 0.1 :9;
A = [916.3, 923.6, 933.1, 947.4, 966.2, 986.6, 1008.5, 1031.5, 1051.3];
A1 = interp1(t ,A , t1) ;
a= 1;
b=9;
h= 1.3;
for i = 0:3
res = 0.5*[A1(a+ i*h)+ A1(a + (i+1)*h)]*h
disp('res')
end

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回答（2 个）

ES
ES 2013-11-7
编辑：ES 2013-11-7
all Indices in matlab must be positive integers. your h is 1.3 so for all i values it will try to access A1(i.3) which is not correct.
res = 0.5*[A1(a+ i*h)+ A1(a + (i+1)*h)]*h
It might help if you say what you ant to achieve in your code. For example
disp('res')
will not give you desired results. It should be
disp(res)
instead.
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ES
ES 2013-11-7
>> size(A1)
ans =
1 81
A1 is a single dimensional array. It has one row and 81 columns. What do you mean by 2nd columns 3 rd reading?
Rizwana
Rizwana 2013-11-7
My mistake. I want to excess 23(2.3) column now. Dont know how to do it. Will try arranging my data in 2D array. If i get stuck again will get back to you. Thank You

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sidra
sidra 2013-11-7
Reading up about matrix indexing will be helpful in your case. Try the link below:
http://www.mathworks.com/help/matlab/math/matrix-indexing.html

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