Why does the sum of S1 AND S2 ?

S1=[23.6000   58.4000   47.4000  101.7000   29.9000   36.8000]
S2=[23.6000   58.4000   47.4000   67.1000   29.9000   71.4000]
c=0;
while ~isequal(S1,S2)
  c=S1+S2
end

2 个评论
显示无隐藏无

John D'Errico 2013-11-8

I think you misunderstand how while works. It cannot loop over the elements of S1 as you have written it.

Azzi Abdelmalek 2013-11-8

I don't know what you want. Can you explain?

请先登录，再进行评论。

Answer 2

Walter Roberson 2013-11-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/105426-why-does-the-sum-of-s1-and-s2#answer_114632

Your while loop does not change S1 or S2, so the body will either not be done at all (if the condition does not hold at the beginning) or will be done repeatedly without end.

4 个评论
显示 2更早的评论隐藏 2更早的评论

Tomas 2013-11-8

编辑：Walter Roberson 2013-11-8

在 MATLAB Online 中打开

THIS IS MY FULL CODE, i don't know to set the while loop, when i have T=6; while not count correctly

clear,clc
MON = [2.8 3.6 17.2;
        5.4 8.3 15.8;
        2.5 3.2 17.6;
        9.9 10.7 13.6;
        5.5 8.9 15.5;
        9.7 11 13.9;
        2.3 3.9 17.9;
        5.7 8.1 15.1;
        9.4 10.5 13;
        9.9 13.2 13.7];
      [m,n]=size(MON)
      T=input('Zadaj počet typickych bodov :')%uzivatel zada koľko chce mať typickych bodov
         for i=1:T %Pociatocne typicke body
          TAZ=MON(1:T,:);
      end
      TAZ
       [r,s]=size(TAZ)%rozmery TAZ
       Z=cell(1,T)%vytvorenie zhlukov
z=1;
          for i=1:m
       for j=1:r
      B = MON(i,:);
      Z1(j)= euklid6(TAZ(j,:),B);%euklidovska vzdialenost
       end
        Z1
        minD = min([Z1]);%minimalna hodnota
        [i_min,j_min]=find(Z1==minD);%indexacia minimalnej hodnoty
        [e,f]=size(Z1);
        %postupne ukladanie podla prislusnosti objektu do zhlukov
        for h=1:f
            if (Z1(h) == Z1(j_min))
            Z{h}{z}=B;
            z=z+1;
            end
        end
       end
        Z;   
        d1=length(Z)
        for i=1:d1 %zmaze prazdne miesta v poli
            Z{i}(cellfun(@isempty,Z{i})) = [];
        end
        Z
      [z1,z2]=size(Z)
      Znew={};%nove pole 
        for j=1:z2
          S1(j)=sucet1(Z(j));
      end
      S1
    S2=0; 
     iter=1;
     while (S1(:,:)~=S2(:,:)) % this while loop is not correctly
        [t1,t2]=size(Z);%rozmery Z
     for j=1:t2
     d(j,:)=tazisko6(Z(j));%vypocet noveho taziska
   end
     d 
[x,y]=size(d)%rozmery d
    w=1;
for i=1:m
 for j=1:x
         B = MON(i,:);
     Z1(j)= euklid6(d(j,:),B);%euklidovska vzdialenost
       end
        Z1
         minD = min([Z1]);%minimalna hodnota
        [i_min,j_min]=find(Z1==minD);%indexacia minimalnej hodnoty
        [e,f]=size(Z1);%rozmery Z1
          %postupne ukladanie podla prislusnosti objektu do zhlukov
        for h=1:f
            if (Z1(h) == Z1(j_min))
            Znew{h}{w}=B;
            w=w+1;
            end
        end
       end
        Znew;
         d2=length(Znew);%zmeria dlzku pola
        for i=1:d2 %zmaze prazdne miesta v poli
            Znew{i}(cellfun(@isempty,Znew{i})) = [];
        end
        Znew;
        Z=Znew
        [b1,b2]=size(Z);
           for j=1:z2
          S2(j)=sucet1(Z(j));
      end
      S2
        iter=iter+1;
       end
        clear,clc
        function [d] = tazisko6(A)
  %%[d] = tazisko6(A)
  %
  % Tazisko jednotlivych zhlukov(centroid)
d1=length(A);
d2 =length(A{1});
     s=0; 
     for i=1:d1
         for j=1:d2
             s=s+(A{i}{j});
         end
         if d2~=1
         d=s/d2;
         else
         d=s;
         end
     end
function [ d] = euklid6( A,B )
%%[d] = euklid(A,B)
%
% Euklidovska vzdialenost bodov
[hA,tA]=size(A);
[hB,wB]=size(B);
if hA==1&hB==1
    d=sqrt(dot((A-B),(A-B)));
else
    C=[ones(1,hB);zeros(1,hB)];
    D=flipud(C);
    E=[ones(1,hA);zeros(1,hA)];
    F=flipud(E);
    G=A*C;
    H=A*D;
    I=B*E;
    J=B*F;
    d=sqrt((G-I').^2+(H-J').^2);
end
end
function [ S1 ] = sucet1( Z1 )
%%S1=sucet(Z1)
n1=length(Z1);
n2=length(Z1{1});
u=0;
for i=1:n1
      for j=1:n2
          u=u+sum(Z1{i}{j});
      end
     S1(i)=u;
end
end

THANKS

Tomas 2013-11-8

编辑：Tomas 2013-11-8

i don't understand english very well :)

Walter Roberson 2013-11-9

在 MATLAB Online 中打开

A = 0.3 - 0.2 - 0.1;
B = 0;
if A == B
  disp('the two are equal')
else
  disp('the two are not equal')
end
if abs(A-B) < eps(0.3)
  disp('the two are approximately equal')
else
  disp('the two are not approximately equal')
end

Do not compare floating point numbers for equality.

Also, you are comparing two arrays. Read the documentation for "if"

An evaluated expression is true when the result is nonempty and contains all nonzero elements (logical or real numeric). Otherwise, the expression is false.

请先登录，再进行评论。

Why does the sum of S1 AND S2 ?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

回答（2 个）

2 个评论
显示无隐藏无

4 个评论
显示 2更早的评论隐藏 2更早的评论

另请参阅

类别

标签

Community Treasure Hunt

Why does the sum of S1 AND S2 ?

0 个评论 显示 -2更早的评论隐藏 -2更早的评论

回答（2 个）

2 个评论 显示 无隐藏 无

4 个评论 显示 2更早的评论隐藏 2更早的评论

另请参阅

类别

标签

Community Treasure Hunt

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

2 个评论
显示无隐藏无

4 个评论
显示 2更早的评论隐藏 2更早的评论