introducing a new variable

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richard
richard 2013-11-13
评论： richard 2013-11-14
I am trying to introduce a new variable that is in terms of a variable that is known.
r''=(-b/a)*r
where r is just a row vector going from -15:15, r'' is the new variable, b&a are the unknown,real constants.
Ultimately I am trying to express a gaussian function in terms of the r=(-a/b)*r'', and take fft's of these gaussian functions.
I have tried using:
syms r'' a b
however when I am trying to take fft's, matlab is unable to do this because a, b, and r'' are syms.
I can't think of another way to introduce this new variable, maybe after the fft of the gaussian is taken? Below is the code I am using but an error comes up at the last two lines. Any help will be appreciated
clear
syms r'' a b real
r=-15:15;
r=-(a/b)*r'';
h=gaussmf(r,[(0.5)/(2*sqrt(2*log(2))),0]);
g=gaussmf(r,[(0.1)/(2*sqrt(2*log(2))),0]);
H=fft(h);
G=fft(G);

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回答（2 个）

Vivek Selvam
Vivek Selvam 2013-11-13
Walter Roberson
Walter Roberson 2013-11-13
I would doubt that you can use r'' as a symbol name. Try using a name that starts with a letter, and consists entirely of letters, digits, or underscores.
  1 个评论
richard
richard 2013-11-14
I have changed my r'' to rr's and the last two lines are still reading out as an error. I changed my code to look life this:
clear
syms rr a b real
rr=-15:15;
r=-(a/b)*rr;
h=gaussmf(r,[(0.5)/(2*sqrt(2*log(2))),0]);
g=gaussmf(r,[(0.1)/(2*sqrt(2*log(2))),0]);
H=fft(h);
G=fft(g);
I have now defined a vector for rr and I want to put r (in terms of a&b the unknown constants, as well as rr) into my gaussian.
In the end, I am wanting to find the function F=G./H, and take f=ifft(F), where f will be in terms of a&b.

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