Cartesian to polar sorting

2 次查看(过去 30 天)
I converted a set of coordinates from Cartesian to polar form
[rho,theta] = cart2pol(x,y);
Next I sorted the polar coordinates
theta_ascend = sort(theta,'ascend');
As in the case of any polar system I will have multiple values of rho for one value of theta. For every value of theta I want to select the maximum value of rho and reject the other values.
for e.g If my values are
theta = 3.14 3.14 3.14 3.13 3.13 3.12 3.12 3.12 . . . rho = 12 15 6 3 5 8 2 11 . . .
I want my output to be theta = 3.14 3.13 3.12 . . . rho = 15 5 11 . . .
Please suggest ?

采纳的回答

Matt Fig
Matt Fig 2011-7-1
As an example:
% First some data to work with:
thet = round(rand(1,10)*3)
r = round(rand(1,10)*30)
% Now match the largest r per unique thet:
M = sortrows([thet.',r.']);
M = M([logical(diff(M(:,1)));true],:)
  1 个评论
Suhas Deshpande
Suhas Deshpande 2011-7-1
For some reason I am not able to convert the sorted polar coordinates to Cartesian
[x,y] = pol2cart(M(:,1),M(:,2))
or
[x,y] = pol2cart(theta,rho)
gives an error
Error: Unexpected MATLAB operator.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Dates and Time 的更多信息

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by