Laplacian and sobel for image processing
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Hello im having trouble finding how to do the laplacian and sobel of an image I tried the following but none of the 2 results are like what is showed in the book The original image i'm working on is image (a)
Code I tried:
img = imread ('imagename'); A=[0 -1 0 ; -1 4 -1 ; 0 -1 0]; result1 = imfilter (img,A); result2 = conv2 (img,A);
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Here are the book results
采纳的回答
Image Analyst
2013-11-25
4 个投票
Well you're not doing the Laplacian or Sobel. Try using the correct kernel and the correct function imgradient). Try the code I wrote for you below in blue.
8 个评论
John Snow
2013-11-25
Ahmed
2014-11-18
Sir, your answer is really good and superb. I really admire your help.
Ali Erdem
2020-5-1
great job, thx.
shyam kumarmanickam
2021-3-21
@Image Analystwhy the low frequency part of image after DWT is blank and when i tried to encrypt that image with hyperchaotic encryption it came that the size not symmetric so i rotated the same image and concad four images as a single image and when i done encryption the histogram came like this.What can be alternative to DWT ?
Image Analyst
2021-3-21
@shyam kumarmanickam I don't think this question of yours on wavelets, chaos, and encryption has anything to do with the original question from @John Snow on x-rays, Sobel filtering, and Laplacian filtering. So you should start your own question and tag it with wavelets, chaos, and encryption. I do not have the Wavelet Toolbox though so I won't be able to help you.
Read this link first though:
bini kif
2021-11-19
@Image Analyst Hello i have a question on the Laplcian why did u divided it by 8
laplacianKernel = [-1,-1,-1;-1,8,-1;-1,-1,-1]/8;
bini kif
2021-11-19
@Image Analyst in test.m
Image Analyst
2021-11-19
To make sure that the output values of hte convolution were in the same range as the input image. Otherwise, worst case where the center value is 255 and the outer values are zero then the output would be 8*255. That is more than the range of the input values. So just to make sure that case would get you a value of 255 instead of 8*255, I divided by 8.
更多回答（1 个）
Bruno Pop-Stefanov
2013-11-25
1 个投票
Make sure img is in right format. imfilter will work on a grayscale uint8 image. However, conv2 will only work on a double image. Use im2double to convert it.
5 个评论
John Snow
2013-11-25
Bruno Pop-Stefanov
2013-11-25
Can you post a link to the image so that I can try?
John Snow
2013-11-25
Image Analyst
2013-11-25
John, my code does exactly what you wanted.
John Snow
2013-11-25
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