HELP WITH ESTRACT SUBSTRING OF STRING

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FRANCISCO
FRANCISCO 2013-12-11
评论： FRANCISCO 2013-12-11
good, I wish to raise my problem, because I know how to do. I, for example have a long string as follows:
[3 -1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4 -1 0 -1 -1 -1 0 -1 -1 3 -1 -1 -1 -1 -1 -1 4 -1 -1 0
-1 1 -1 -1 -1 0 -1 1 -1 -1 -1 -1 -1 -1 1 -1 0 -1 -1 4……..
What I want to do is the following:
1) extracting substrings so that starts for next 3/4 and ends 3/4 including the upcoming latter. For example:
[-1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4]
Next substring;
[-1 0 -1 -1 -1 0 -1 -1 3]
Next substring;
[-1 -1 -1 -1 -1 -1 4]
And so on

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回答（3 个）

Walter Roberson
Walter Roberson 2013-12-11
http://www.mathworks.com/help/matlab/matlab_prog/regular-expressions.html#brchk1t
regexp(String, '(?<=[34]).*?[34]', 'match')
Or so I figure as I drift off to sleep.
Andrei Bobrov
Andrei Bobrov 2013-12-11
a = [3 -1 -1 -1 -1 -1 1 -1 -1 -1 0 -1 -1 -1 -1 4 -1 0 -1 -1 -1 0 -1 -1 3 -1 -1 -1 -1 -1 -1 4 -1 -1 0 -1 1 -1 -1 -1 0 -1 1 -1 -1 -1 -1 -1 -1 1 -1 0 -1 -1 4];
l = a == 3 | a== 4;
l(2:end-1) = circshift(l(2:end-1),[0 1]);
l(end) = 0;
out = accumarray(cumsum(l(:)),a(:),[],@(x){x});
  2 个评论
FRANCISCO
FRANCISCO 2013-12-11
编辑：FRANCISCO 2013-12-11
I wanted to ask something else I do not know how I can do it :
The end result should look like the following , for example :
a) [ -1 -1 -1 0 -1 1 -1 4 ] started with this sequence
MATRIX1 ( the length of the substring is n = 3)
PATTERN________________OCCURS________________________-Nº(-1)
0 1 4---------------------------------------1----------------------------------------------------5
eliminating pattern we get (-1 ) So if another pattern appears the same size as this matrix include , for example :
b) [-1 -1 1 -1 0 3]
PATTERN________________OCCURS________________________-Nº(-1)
0 1 4---------------------------------------1----------------------------------------------------5
1 0 3---------------------------------------1----------------------------------------------------3
So if another pattern appears, but of varying length I store in another array , for example :
c ) [ 1 -1 0 -1 -1 -1 1 -1 4]
MATRIX2 ( the length of the substring is n = 4)
PATTERN________________OCCURS________________________-Nº(-1)
1 0 1 4---------------------------------------1---------------------------------------------------5
My question is, how can I remove the numbers with a loop (-1) for the pattern, and I store it in another array each pattern of the same length?
Before deleting (-1) should make a count and associate to pattern.
Many thanks
FRANCISCO
FRANCISCO 2013-12-11
To count (-1) I used:
if true
% code
n=length(out);
for i=1:n;
gg=out(i,1);
gg=cell2mat(gg);
menos1(i)=numel(gg(gg==-1));
end
menos1=menos1';
end
And to remove (-1) I tried to use this code but matlab gives me error
if true
% code
out1=out;
n=length(out1);
for i=1:n;
gg=out1(i,1);
gg=cell2mat(gg);
gg(gg(i)==-1)=[];
end
end
Many thanks

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Jos (10584)
Jos (10584) 2013-12-11
If you have version 2013b, there is a function called strsplit , that might work on numerical arrays (like strfind used to do). I cannot test this, though.
C = strsplit(str,[3 4])

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