how can i use multiple expression values in If-then

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Syed Kaleem Gilani
Syed Kaleem Gilani 2013-12-13
编辑： Syed Kaleem Gilani 2013-12-14
I will post my code that i made, im a noob. just take my "||" as or in english, thats what i think of it, but it dont work, it only gives me 'NORTH' for any value please check and correct..It is m,y university assignment.
function[r]=direction(bearing)
if bearing == 0 || 360
r= 0 || 360;
printf('North\n')
elseif bearing== 90 || -270
r= 90 || -120;
printf('East\n')
elseif bearing== 180 || -180
r= 180 || -180;
printf('South\n')
elseif bearing== 270 || -90
r= 270 || -90;
printf('West\n')
else
printf('Unknown Direction\n')
end

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采纳的回答

Syed Kaleem Gilani
Syed Kaleem Gilani 2013-12-14
编辑：Syed Kaleem Gilani 2013-12-14
I found the solution, BTW thank you so much @paul and @ jos(10584)
function[]=direction(bearing)
if (bearing == 0 || bearing==360)
disp('North\n')
elseif (bearing== 90 || bearing ==-270)
disp('East\n')
elseif (bearing== 180 || bearing== -180)
disp('South\n')
elseif (bearing== 270 || bearing== -90)
disp('West\n')
else
disp('Unknown Direction\n')
end
%it works fine

更多回答（2 个）

Jos (10584)
Jos (10584) 2013-12-13
This should get you started:
if A==1 || A == 2
disp('A is 1 or 2') ;
end
if B == 1 && C == 2
disp('B is 1 and C is 2') ;
end
  1 个评论
Jos (10584)
Jos (10584) 2013-12-13
btw , the reason why you get 'North' all the time is because the condition
bearing == 0 || 360
is equal
bearing == 0 || true
which is always true of course.

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Paul
Paul 2013-12-13
function[r]=direction(bearing)
if bearing == 0 | | bearing==360
r= 0;
fprintf('North\n')
elseif bearing== 90 | | bearing==-270;
r= 90;
fprintf('East\n')
elseif bearing== 180 | | bearing== 180;
r= 180;
fprintf('South\n')
elseif bearing== 270 | | bearing== -90 ;
r= 270;
fprintf('West\n') ;
else printf('Unknown Direction\n')
end
I think that's what you want unless you want to define r as a string ?

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